Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
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Chapter 15, Problem 1P

(a)

To determine

The change in the internal energy of the gas.

(a)

Expert Solution
Check Mark

Answer to Problem 1P

The change in the internal energy of the gas is 0J .

Explanation of Solution

Given info:

The change in the temperature is, ΔT=0°C .

Formula Used:

The expression to calculate the change in the internal energy of the gas is,

  ΔU=mcΔT

Here, m is the mass of the gas, c is the specific heat of the gas.

Calculation:

Substitute all the values in the above expression.

  ΔU=mc(0°C)=0J

Conclusion:

Thus, the change in the internal energy of the gas is 0J .

(b)

To determine

The heat absorbed during expansion of gas.

(b)

Expert Solution
Check Mark

Answer to Problem 1P

The heat absorbed during expansion of the gas is 3.40×103J .

Explanation of Solution

Given info:

The work done by the gas in expansion process is, W=3.40×103J .

Formula Used:

The expression to calculate the heat absorbed during expansion of the gas is,

  Q=ΔU+W

Calculation:

Substitute all the values in the above expression.

  Q=0J+3.40×103J=3.40×103J

Conclusion:

Thus, the heat absorbed during expansion of the gas is 3.40×103J .

Chapter 15 Solutions

Physics: Principles with Applications

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