Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 15, Problem 12Q

(a)

To determine

To find: The change in entropy.

(a)

Expert Solution
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Explanation of Solution

As entropy is defined as change in heat at particular temperature, in an adiabatic process ΔQ=0 .

Hence, entropy change ΔS=ΔQΔT=0 .

It means entropy stay same

(b)

To determine

To find: The change in entropy.

(b)

Expert Solution
Check Mark

Explanation of Solution

Formula used: ΔS=nRLnVfVi

Calculation: If Vf>Vi then entropy will increase.

When we expand the gas iso-thermally then change in entropy =nrln(v2/v1) .

If v2/v1 then entropy will increase.

Thus, entropy change = ΔS=ΔQΔT=increase.

Chapter 15 Solutions

Physics: Principles with Applications

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