Chapter 1.5, Problem 38E

a.

To determine

To write an equation that relates g and t .

Answer to Problem 38E

  $55t=20g$

Explanation of Solution

Given information :

  

Here it is given that,

  $\begin{array}{l}d=55t\\ d=20g\end{array}$

Hence we shall equate both, we get,

  $55t=20g$

b.

To determine

To solve the equation for g .

Answer to Problem 38E

  $g=2.75t$

Explanation of Solution

Given information :

  

We know,

  $55t=20g$

Now we shall solve for g , we get,

  $\begin{array}{l}55t=20g\\ g=\frac{55t}{20}\\ g=2.75t\end{array}$

c.

To determine

To determine the gasoline used and the distance travelled by the car.

Answer to Problem 38E

Distance travelled is 330 miles.

Gasoline used is 16.5 gallons.

Explanation of Solution

Given information :

  

Here it is given that,

  $\begin{array}{l}d=55t\\ d=20g\end{array}$

Now we shall put $t=6$ in the given equation we get the distance as,

  $\begin{array}{l}d=55\left(6\right)\\ d=330\text{ miles}\end{array}$

Now the gasoline used is,

  $\begin{array}{l}g=2.75t\\ g=2.75\left(6\right)=16.5\text{ gallons}\end{array}$