WTCC BIOLOGY PACKAGE W/ ACCESS >C<
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ISBN: 9781269715485
Author: Urry
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Chapter 15.3, Problem 2CC
VISUAL SKILLS Ø For each type of offspring of the test-cross in Figure 15.9, explain the relationship between its
Figure 15.9 Inquiry How does linkage between two genes affect inheritance of characters?
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Interpret the result of your Chi-squared test. How many gene pairs were responsible for eye color in flies as associated with sex? What gene interaction was present in the gene/s for eye color? What is the genotype of the possible P1 & P2 that produced this F2 population? (Remember to indicate your gene notation).
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A red flowered plant was crossed with a blue flowered plant and produced all purple flowered plants. When the purple flowered plants were crossed with each other they produced 5 red plants, 5 blue plants, 20 deep purple plants, 20 light lilac plants, and 30 purple plants
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2. Devise a simple method to calculate the total number of offspring genotypes and the total number of phenotypes (assuming complete dominance of Q, R and T) produced in the following cross without completing a branch diagram?
q q R r Tt X Q Q r r T t
Chapter 15 Solutions
WTCC BIOLOGY PACKAGE W/ ACCESS >C<
Ch. 15.1 - Which one of Mendel's laws describes the...Ch. 15.1 - MAKE CONNECTIONS Review the description of...Ch. 15.1 - WHAT IF? Propose a possible reason that the first...Ch. 15.2 - A white-eyed female Drosophila is mated with a...Ch. 15.2 - Neither Tim nor Rhoda has Duchenne muscular...Ch. 15.2 - MAKE CONNECTIONS Consider what you learned about...Ch. 15.3 - When two genes are located on the same chromosome,...Ch. 15.3 - VISUAL SKILLS For each type of offspring of the...Ch. 15.3 - Prob. 3CCCh. 15.4 - Prob. 1CC
Ch. 15.4 - Prob. 2CCCh. 15.4 - Prob. 3CCCh. 15.5 - Gene dosagethe number of copies of a gene that are...Ch. 15.5 - Reciprocal crosses between two primrose varieties,...Ch. 15.5 - WHAT IF? Mitochondrial genes are critical to the...Ch. 15 - What characteristic of the sex chromosomes allowed...Ch. 15 - Why are males affected by X-Iinked disorders much...Ch. 15 - Why are specific alleles of two distant genes more...Ch. 15 - Prob. 15.4CRCh. 15 - Explain how genomic imprinting and inheritance of...Ch. 15 - A man with hemophilia (a recessive, sex-linked...Ch. 15 - Pseudohypertrophic muscular dystrophy is an...Ch. 15 - A wild-type fruit fly (heterozygous for gray body...Ch. 15 - A planet is inhabited by creatures that reproduce...Ch. 15 - Using the information from problem 4, scientists...Ch. 15 - A wild-type fruit fly (heterozygous for gray body...Ch. 15 - Assume that genes, A and B are on the same...Ch. 15 - Two genes of a flower, one Controlling blue (B)...Ch. 15 - You design Drosophila crosses to provide...Ch. 15 - Banana plants, which are triploid, are seedless...Ch. 15 - EVOLUTION CONNECTION Crossing over is thought to...Ch. 15 - SCIENTIFIC INQUIRY DRAW IT Assume you are mapping...Ch. 15 - WRITE ABOUT A THEME: INFORMATION The continuity of...Ch. 15 - SYNTHESIZE YOUR KNOWLEDGE Butter flies have an X-Y...
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- Give typed full explanation You are studying three linked genes in snapdragons. The flower color locus is in the center. There are 13.8 cM between the flower color locus and the plant height locus. There are 14.5 cM between the flower color locus and the leaf type locus. The coefficient of coincidence is 0.8. Pure-breeding tall, red-flowered plants with fuzzy leaves were crossed to pure-breeding dwarf, blue-flowered plants with smooth leaves. The F1 were testcrossed. Calculate the proportion of the testcross progeny that are expected to be dwarf with red flowers. Round properly to 4 decimal digits.arrow_forwardBackground: Each kernel on a cob of corn is a seed for a corn plant. Each kernel can be planted and a whole new corn plant can grow from this kernel. Each cob of corn has hundreds of kernels which were each created by the fertilization of hundreds of eggs from one corn plant and hundreds of pollen from another corn plant. Corn cobs allow for easy genetic analysis because looking at a corn cob is like looking at the hundreds of offspring created from two parents. Corn kernels can come in different colours and textures. It has been determined that purple (P) corn kernels are dominant to yellow (p) corn kernels. Smooth (M) kernels are dominant to shrunken (m) kernels. Purpose: With the use of chi-square analysis, determine if one should accept or reject the hypothesis that both parents that created a cob of corn were heterozygous for colour and heterozygous for texture (PpMm X PpMm). Apparatus & Method: Create a dihybrid cross and determine the expected phenotypic…arrow_forwardGene mapping using the Three-point Testcross a) Given the following alleles that control seed traits:W = wrinkled G = green R = roundw = smooth g = yellow r = oval b) Results of a cross with a triple heterozygote revealed the following phenotypes:30 smooth yellow round4 smooth green round958 wrinkled green round2 wrinkled yellow oval18 wrinkled yellow round946 smooth yellow oval16 smooth green oval26 wrinkled green oval c) Determine the order of the genes and the distance between them in centiMorgan (cM).Construct a gene map to show your results. TIP: Based on the phenotypes, determine the alleles in the gametesarrow_forward
- WHAT IF? If the parental (P generation) flies had been true-breedingfor gray body with vestigial wings and black body with normal wings, whichphenotypic class(es) would be largest among the testcross offspring?arrow_forwardDetermining Genotype Directions: Determine the genotype of the gametes that will come from parent 1 and parent 2. Then perform a cross using the punnett square to determine the genotype and phenotype of the offspring Check the picturesarrow_forwardBased on MS- LS3-1 Can you make a model that shows how blue eyes originated? Can you include genes, chromosomes, traits, proteins, and organisms? Can you Include a Punnett Square to show how this trait could be passed on to the next generation? Note: can you include the drawing as question is suggested? can it be simpler for grade 8 levelarrow_forward
- select whcih ic correct When 2 wildtype alleles are on the same parental chromosome, this is known as [Combined or Coupling or dispersed or heterozygous or Repulsion] . In sharp contrast [Combined or Coupling or dispersed or heterozygous or Repulsion] is when 1 wildtype allele and 1 mutant allele are on the same parental chromosomearrow_forwardTOPIC: GENE INTERACTION AND EPISTASIS Two pure-breeding (homozygous) lines of shrubs were crossed as follows: P1 phenotype red leaves X green leaves P1 genotype ___________ _____________ F1 phenotype 100% green leaves with white flecks F1 genotype ___________ Crossing the F1s produced: F2 phenotypes F2 genotypes 123 green leaves w/ white flecks ____ 44 green leaves ____ 63 red leaves ____arrow_forwardSummary IntroductionTo determine:Whether the given statement “All traits are inherited in a Mendelian pattern.” is true or false.Introduction:Some traits are transferred to the offspring from their parents; this process is called inheritance. Mendel gave some laws to describe how genetic transmission of traits take place, the inheritance pattern that follows the law of Mendel is known as Mendelian inheritance. Mendel gave the law of segregation, the law of dominance, and the law of independent assortment.arrow_forward
- QUANTITATIVE Recall that hemophilia is an X-linked recessive disease. If a woman with hemophilia had children with a man without hemophilia, what is the chance that their first child will have the disease? What is the chance that their first child will be a carrier?arrow_forwardNeed help Q1: Assuming these two genes sort independently, how many progeny would you expect to show the green striped phenotype? (Enter your answers as a whole number, e.g. 1) Q2: Which of the following are recombinant phenotypes? (Select all that apply) A. Green and Spotted B. Green and Striped C. Yellow and Spotted: D. Yellow and Stripedarrow_forwardTOPIC: GENE INTERACTION AND EPISTASIS In pineapples, leaves may be spiny, spiny-tipped or piping. Pineapples of different phenotypes were used in the following crosses: P1 phenotype piping X spiny P1 genotype ______ ______ F1 phenotype 100% piping F1 genotype ______ Crossing the F1s produced: F2 phenotypes F2 genotypes 95 piping _______ 25 spiny tipped _______ 8 spiny _______arrow_forward
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