PRINCIPLES OF BIOLOGY TEXT & CODE
16th Edition
ISBN: 9781269502528
Author: Pearson
Publisher: PEARSON
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Chapter 16, Problem 16.2CR
DRAW IT Ø Redraw the Punnett Square on The right side of Figure 14.8 as two smaller monohybrid Punnett squares, one for each gene. Below each square. list the fractions of each
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Chapter 16 Solutions
PRINCIPLES OF BIOLOGY TEXT & CODE
Ch. 16.1 - Given a polynucleotide sequence such as GAATTC,...Ch. 16.1 - VISUAL SKILLS Griffith was trying to develop a...Ch. 16.2 - What role does complementary base pairing play in...Ch. 16.2 - Identify two major functions of DNA pol III in DNA...Ch. 16.2 - Prob. 3CCCh. 16.2 - Prob. 4CCCh. 16.3 - Describe the structure of a nucleosome, the basic...Ch. 16.3 - What two properties, one structural and one...Ch. 16.3 - MAKE CONNECTIONS Interphase chromosomes appear to...Ch. 16 - What does it mean wheti we say that the two DNA...
Ch. 16 - DRAW IT Redraw the Punnett Square on The right...Ch. 16 - Describe the levels of chromatin packing you'd...Ch. 16 - In his work with pneumonia-causing bacteria and...Ch. 16 - What is the basis for tlie difference in how the...Ch. 16 - In analyzing the number of different bases in a...Ch. 16 - The elongation of the leading Strand during DNA...Ch. 16 - In a nucleosome, the DNA is wrapped around (A)...Ch. 16 - E. coli cells grown on, 15N medium are transferred...Ch. 16 - A biochemist isolates, purifies, and combines in a...Ch. 16 - The spontaneous loss of amino groups from adenine...Ch. 16 - MAKE CONNECTIONS Although the proteins that cause...Ch. 16 - EVOLUTION CONNECTION Some bacteria may be able to...Ch. 16 - SCIENTIFIC INQUIRY DRAW IT Model building can be...Ch. 16 - Prob. 12TYUCh. 16 - Prob. 13TYU
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- Topic: Trihybrid Cross, Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The fraction of The F1 progenty will be ? Pls explain it with more details. thanksarrow_forwardFigure shows a dihybrid cross but it can be analyzed as a monohybrid cross of just smooth seed coat (S) and wrinkled seed coat (s) with complete dominance that should show a 1:2:1 ratio. Examine Figure and see if you can find these results. Likewise, it can be analyzed as a monohybrid cross of yellow seed coat versus green. Can you find these in the expected ratio?arrow_forwardThe genotype of F1 individuals in a tetrahybrid cross isAaBbCcDd. Assuming independent assortment of these fourgenes, what are the probabilities that F2 offspring will have thefollowing genotypes?(a) aabbccdd(b) AaBbCcDd(c) AABBCCDD (d) AaBBccDd(e) AaBBCCddarrow_forward
- The genotype of F1 individuals in a tetrahybrid cross isAaBbCcDd. Assuming independent assortment of these fourgenes, what are the probabilities that F2 offspring will have thefollowing genotypes?(a) aabbccdd(b) AaBbCcDd(c) AABBCCDDarrow_forwardYou may insert a hand-drawn diagram of your map, but the rest of the assignment must be fully typed. The data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable.arrow_forwardNotation: D = disease allele at gene d = wild-type allele at gene Let’s provide some information about each MOI. AD: Each of the F1 parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother’s genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female 301 Total 1157 DF p-value In Table 2, provide expected proportions for two different MOIs: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected)…arrow_forward
- Figure 8.9 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. You end up with three plants, all which have round peas. From this data, can you tell if the parent plant is homozygous dominant or heterozygous?arrow_forwardMore Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross in pea plants, in which smooth pea shape is dominant to wrinkled, and yellow pea color is dominant to green. A plant with smooth yellow peas is crossed to a plant with wrinkled green peas. The offspring produced peas that were all smooth and yellow. What are the genotypes of the parents? What are the genotypes of the offspring?arrow_forwardImagine that you are performing a cross involving seed texture in garden pea plants. You cross true-breeding round and wrinkled parents to obtain F1 offspring. Which of the following experimental results in terms of numbers of plants are closest to what you expect in the F2 progeny? a. 8lOroundseeds b. 8lOwrinkledseeds c. 405:395 round seeds:wrinkled seeds d. 610:190 round seeds:wrinkled seedsarrow_forward
- In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?arrow_forwardIn an autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for redstigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploidstrain. Show all solutions and label solutions and final answers properly.a. What is the genotype of the F1?b. Derive the types of gametes the F1’s may be expected to form and the proportion of each.c. What are the expected genotypic ratio, and phenotypic ratio of green to red if:i. the F1’s are intercrossed?ii. the F1’s are crossed with red plants?d. If the G locus were 50 or more map units from the centromere, what types and proportions ofgametes would the F1 be expected to produce? Derive the expected F2 genotypic and phenotypicratios. Please answer letter d only.arrow_forwardTopic: Trihybrid Cross, Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The F1 progenty: 27/64 will be as tall as the parents; 37/64 will be shorter than the parents. Pls explain it with more details. thanksarrow_forward
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