Chapter 1.6, Problem 19P

To determine

To calculate:Hockey matches Won, Loosed and Tied.

Answer to Problem 19P

Hockey matches won is $\frac{17}{3}=5.66$

Hockey matches loosed is $\frac{11}{3}=3.66$

Hockey matches tied is $\frac{8}{3}=2.66$

Explanation of Solution

Given information:

The total matches played is 12. Matches won is two more than they lost and matches lost is one more than they tied.

Calculation:

Let us assume that the matches tied be x, so matches lost is $(x+1)$ and matches won is $2+(x+1)=3+x$

So, According to question,

  $\begin{array}{l}x+1+x+3+x=12\\ \Rightarrow 3x+4=12\\ \Rightarrow 3x=12-4\\ \Rightarrow 3x=8\\ \Rightarrow x=\frac{8}{3}=2.66\end{array}$

Since, $x=\frac{8}{3}$

Therefore, matches tied is $\frac{8}{3}$ .

As lost is $\text{(x+1)}$

So, putting the value of x in the above equation we get-

  $1+\frac{8}{3}=\frac{3+8}{3}=\frac{11}{3}=3.66$

Therefore, matches lost is $\frac{11}{3}$

And matches won is $3+x$

So,putting the value of x in the above equation we get,

  $3+\frac{8}{3}=\frac{9+8}{3}=\frac{17}{3}=5.66$

Therefore, matches won is $\frac{17}{3}$

So, the required answer is

Hockey matches won is $\frac{17}{3}=5.66$

Hockey matches loosed is $\frac{11}{3}=3.66$

Hockey matches tied is $\frac{8}{3}=2.66$