Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 1.7, Problem 12P

To determine

To calculate: Solve using the five-stepplan.Leah and barb started at school and jogged in opposite directions. After 30 min they were 10.5 km farther than Leah. How far did each jog? Choices for Leah's distance: 4.5, 4.6, 4.7

Expert Solution & Answer

Answer to Problem 12P

The distance jogged by Leah is a=4.5 and the distance jogged by Barb is a+1.5=4.5+1.5=6

Explanation of Solution

Given information:Leah and barb started at school and jogged in opposite directions. After 30 min they were 10.5 km farther than Leah.

Calculation:

Step 1: Here we have two unknowns, distance jogged by Leah and distance jogged by Barb.

Step 2: Let a be the distance jogged by Leah and a+1.5 be the distance jogged by Barb.

Step 3: As given, after 30 min they were 10.5 km farther than Leah such that a+(a+1.5)=10.5

Step 4: Choices for a are given as 4.5, 4.6, 4.7

a	a+(a+1.5)=10.5	True / False
4.5	4.5+(4.5+1.5)=10.5	True
4.6	4.6+(4.6+1.5)=10.5 10.7≠10.5	False
4.7	4.7+(4.7+1.5)=10.5 10.9≠10.5	True

From above table we can say that the distance jogged by Leah is a=4.5 and the distance jogged by Barb is a+1.5=4.5+1.5=6

Step 5: Now we verify the answer

Barb travelled 1.5 km farther than Leah: 6−4.5=1.5 , which is correct

After 30 minutes they were 10.5 km apart: 4.5+6=10.5 , which is also correct.

Chapter 1.7, Problem 11P

Chapter 1.7, Problem 13P

Chapter 1 Solutions

Algebra: Structure And Method, Book 1

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ISBN:9780134463216

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Publisher:PEARSON

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