Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 1.7, Problem 5P

To determine

To calculate: Solve using the five-step plan. Write out each step. A choice of possible numbers for one unknown is given.A bus went 318 km farther than a car. The car went one third as far as the bus. How far the car's distance: 147, 151, 159

Expert Solution & Answer

Answer to Problem 5P

The distance car travelled is a=159 and the distance bus travelled is 159+318=159*3=477

Explanation of Solution

Given information:A bus went 318 km farther than a car and the car went one third as far as the bus.

Calculation:

Step 1: Here we have two unknowns, distance travelled by the car and distance travelled by the bus.

Step 2: Let a be the distance travelled by the car and a+318 be the distance travelled by the bus.

Step 3: As given, the car went one third as far as the bus such that a=318=3a .

Step 4: Choices for a are given as 147, 151, 159.

a	a+318=3(a)	True / False
147	147+318=3(147)	False
151	151+318=3(151)	False
159	151+318=3(159)	True

From above table we can say that the distance car travelled is a=159 and the distance bus travelled is 159+318=159*3=477

Step 5: Now we verify the answer

The bus travelled 318 km farther than the car: 477−159=318 , which is correct

The car went one third as far as the bus: 13(477)=159 , which is also correct.

Chapter 1.7, Problem 4P

Chapter 1.7, Problem 6P

Chapter 1 Solutions

Algebra: Structure And Method, Book 1

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