Chemistry: The Molecular Nature of Matter and Change
Chemistry: The Molecular Nature of Matter and Change
8th Edition
ISBN: 9781259631757
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 17, Problem 17.104P

(a)

Interpretation Introduction

Interpretation:

Kp for the given reaction 2NO(g) + O2(g)  2NO2(g) has to be calculated.

Concept Introduction:

The relation between Kp and Kc is given by the following equation.

Kp = Kc(RT)Δngas Kp = Equilibrium constant in terms of partial pressureKc = Equilibrium constant in terms of concentrationΔngas = moles of gaseous product  moles of gaseous reactant

Only moles of gaseous products and reactants are used for calculating Δngas.

(a)

Expert Solution
Check Mark

Answer to Problem 17.104P

Kp for the given reaction is 4.9×105.

Explanation of Solution

Given data is shown below:

  2NO(g) + O2(g)  2NO2(g)Kp = 1.3×104T = 457 K

  • Determine Δngas:

The total number of moles of gaseous reactants is 3 and the moles of gaseous product is 2.  Δngas is determined as follows,

  Δngas  = moles of gaseous product - moles of gaseous reactant =23 =1

  • Determine Kp:

Kp of the reaction can be determined from given Kc as below,

  Kp = Kc(RT)Δngas= (1.3×104)[(0.0821 atm.L/mol.K)(457 K)]1 = 4.9×105

Therefore,

Kp for the given reaction is 4.9×105.

(b)

Interpretation Introduction

Interpretation:

Standard heat of formation for the given reaction , 2NO(g) + O2(g)  2NO2(g) has to be calculated.

Concept Introduction:

The value of standard heat of formation ΔHο of the given reaction is calculated by the formula,

ΔHο=npΔHfο(products)nrΔHfο(reactants)

Where,

ΔHfο(reactants)=the standard enthalpy of formation for the reactantsΔHfο(products)=the standard enthalpy of formation for the productsnp=number of products moleculenr=number of reactants molecule

(b)

Expert Solution
Check Mark

Answer to Problem 17.104P

Standard heat of formation for the given reaction is -114.2 kJ.

Explanation of Solution

Given data is shown below:

  2NO(g) + O2(g)  2NO2(g)ΔHfo[NO2(g)] = 33.2 kJ/molΔHfo[NO(g)] = 90.29 kJ/molΔHfo[O2(g)] = 0 kJ/mol

Standard heat of formation for the given reaction can be determined given below,

  ΔHrxno=npΔHfο(products)nrΔHfο(reactants)= (2×ΔHfo[NO2(g)])[(2×ΔHfo[NO(g)])+ΔHfo[O2(g)]]= (2 mol×33.2 kJ/mol)[(2 mol×90.29 kJ/mol)+(1 mol×0 kJ/mol)]= 114.2 kJ

Therefore,

Standard heat of formation for the given reaction is -114.2 kJ.

(c)

Interpretation Introduction

Interpretation:

Temperature at which Kc= 6.4×109 for the reaction 2NO(g) + O2(g)  2NO2(g) has to be calculated.

Concept Introduction:

The van’t Hoff Equation: Effect of temperature on equilibrium constant can be shown as follows,

  lnK2K1=ΔHrxnoR(1T21T1)where,K1 = Equilibrium constant at T1K2 = Equilibrium constant at T2ΔHrxno=Standard heat of formationfor the given reaction

(c)

Expert Solution
Check Mark

Answer to Problem 17.104P

Standard heat of formation for the given reaction is -114.2 kJ.

Explanation of Solution

Given data is shown below:

  2NO(g) + O2(g)  2NO2(g)ΔHrxno = 114.2 kJT1 = 457 KK1 at 457 K = 4.9×105K2= 6.4×109

Temperature at which Kc= 6.4×109 for given reaction can be determined given below,

  lnK2K1=ΔHrxnoR(1T21T1)ln6.4×1094.9×105=114.2 kJ(8.314 J/mol K)(1T21457 K)T2 = 347.4 K

Therefore,

Temperature at which Kc= 6.4×109 for given reaction is 347.4 K.

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Chapter 17 Solutions

Chemistry: The Molecular Nature of Matter and Change

Ch. 17.5 - Prob. 17.6AFPCh. 17.5 - Prob. 17.6BFPCh. 17.5 - Prob. 17.7AFPCh. 17.5 - Prob. 17.7BFPCh. 17.5 - Prob. 17.8AFPCh. 17.5 - Prob. 17.8BFPCh. 17.5 - Prob. 17.9AFPCh. 17.5 - Prob. 17.9BFPCh. 17.5 - An inorganic chemist studying the reactions of...Ch. 17.5 - A chemist studying the production of nitrogen...Ch. 17.6 - In a study of glass etching, a chemist examines...Ch. 17.6 - Prob. 17.11BFPCh. 17.6 - Prob. 17.12AFPCh. 17.6 - Prob. 17.12BFPCh. 17.6 - Prob. 17.13AFPCh. 17.6 - Should T be increased or decreased to yield more...Ch. 17.6 - Prob. 17.14AFPCh. 17.6 - Prob. 17.14BFPCh. 17.6 - Many metabolites are products in branched...Ch. 17 - Prob. 17.1PCh. 17 - When a chemical company employs a new reaction to...Ch. 17 - If there is no change in concentrations, why is...Ch. 17 - Prob. 17.4PCh. 17 - Prob. 17.5PCh. 17 - Prob. 17.6PCh. 17 - Prob. 17.7PCh. 17 - Prob. 17.8PCh. 17 - Prob. 17.9PCh. 17 - Does Q for the formation of 1 mol of NO from its...Ch. 17 - Does Q for the formation of 1 mol of NH3 from H2...Ch. 17 - Balance each reaction and write its reaction...Ch. 17 - Prob. 17.13PCh. 17 - Prob. 17.14PCh. 17 - Prob. 17.15PCh. 17 - At a particular temperature, Kc = 1.6×10−2...Ch. 17 - Prob. 17.17PCh. 17 - Balance each of the following examples of...Ch. 17 - Balance each of the following examples of...Ch. 17 - Balance each of the following examples of...Ch. 17 - Balance each of the following examples of...Ch. 17 - Prob. 17.22PCh. 17 - Prob. 17.23PCh. 17 - Prob. 17.24PCh. 17 - Prob. 17.25PCh. 17 - When are Kc and Kp equal, and when are they not? Ch. 17 - A certain reaction at equilibrium has more moles...Ch. 17 - Prob. 17.28PCh. 17 - Determine Δngas for each of the following...Ch. 17 - Prob. 17.30PCh. 17 - Prob. 17.31PCh. 17 - Prob. 17.32PCh. 17 - Prob. 17.33PCh. 17 - Prob. 17.34PCh. 17 - The following molecular scenes depict the aqueous...Ch. 17 - At 425°C, Kp = 4.18 × 10−9 for the...Ch. 17 - At 100°C, Kp = 60.6 for the reaction 2NOBr(g) ⇌...Ch. 17 - The water-gas shift reaction plays a central role...Ch. 17 - In the 1980s, CFC-11 was one of the most heavily...Ch. 17 - For a problem involving the catalyzed reaction of...Ch. 17 - What is the basis of the approximation that avoids...Ch. 17 - Prob. 17.42PCh. 17 - Gaseous ammonia was introduced into a sealed...Ch. 17 - Prob. 17.44PCh. 17 - Prob. 17.45PCh. 17 - Prob. 17.46PCh. 17 - Prob. 17.47PCh. 17 - Prob. 17.48PCh. 17 - Prob. 17.49PCh. 17 - Prob. 17.50PCh. 17 - Nitrogen dioxide decomposes according to the...Ch. 17 - Hydrogen iodide decomposes according to the...Ch. 17 - Compound A decomposes according to the...Ch. 17 - In an analysis of interhalogen reactivity, 0.500...Ch. 17 - A toxicologist studying mustard gas, S(CH2CH2Cl)2,...Ch. 17 - Prob. 17.56PCh. 17 - A key step in the extraction of iron from its ore...Ch. 17 - What does “disturbance” mean in Le Châtelier’s...Ch. 17 - Prob. 17.59PCh. 17 - Prob. 17.60PCh. 17 - Prob. 17.61PCh. 17 - Le Châtelier’s principle is related ultimately to...Ch. 17 - An equilibrium mixture of two solids and a gas, in...Ch. 17 - Consider this equilibrium system: CO(g) + Fe3O4(s)...Ch. 17 - Sodium bicarbonate undergoes thermal decomposition...Ch. 17 - Prob. 17.66PCh. 17 - Prob. 17.67PCh. 17 - Predict the effect of decreasing the container...Ch. 17 - Prob. 17.69PCh. 17 - Prob. 17.70PCh. 17 - Prob. 17.71PCh. 17 - Prob. 17.72PCh. 17 - Prob. 17.73PCh. 17 - Prob. 17.74PCh. 17 - The formation of methanol is important to the...Ch. 17 - Prob. 17.76PCh. 17 - The oxidation of SO2 is the key step in H2SO4...Ch. 17 - A mixture of 3.00 volumes of H2 and 1.00 volume of...Ch. 17 - You are a member of a research team of chemists...Ch. 17 - For the following equilibrium system, which of the...Ch. 17 - Prob. 17.81PCh. 17 - Prob. 17.82PCh. 17 - Prob. 17.83PCh. 17 - Prob. 17.84PCh. 17 - Prob. 17.85PCh. 17 - Prob. 17.86PCh. 17 - Prob. 17.87PCh. 17 - Prob. 17.88PCh. 17 - When 0.100 mol of CaCO3(s) and 0.100 mol of CaO(s)...Ch. 17 - Prob. 17.90PCh. 17 - Prob. 17.91PCh. 17 - Prob. 17.92PCh. 17 - Highly toxic disulfur decafluoride decomposes by a...Ch. 17 - A study of the water-gas shift reaction (see...Ch. 17 - Prob. 17.95PCh. 17 - Prob. 17.96PCh. 17 - Prob. 17.97PCh. 17 - Prob. 17.98PCh. 17 - Prob. 17.99PCh. 17 - Prob. 17.100PCh. 17 - The molecular scenes below depict the reaction Y ⇌...Ch. 17 - For the equilibrium H2S(g) ⇌ 2H2(g) + S2(g) Kc =...Ch. 17 - Prob. 17.103PCh. 17 - Prob. 17.104PCh. 17 - The kinetics and equilibrium of the decomposition...Ch. 17 - Isopentyl alcohol reacts with pure acetic acid to...Ch. 17 - Isomers Q (blue) and R (yellow) interconvert. They...Ch. 17 - Glauber’s salt, Na2SO4·10H2O, was used by J. R....Ch. 17 - Prob. 17.109PCh. 17 - Synthetic diamonds are made under conditions of...
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