COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 17, Problem 21QAP
To determine
The effect on the potential energy and electric potential when a positive charge is moving in the direction of electric field.
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Chapter 17 Solutions
COLLEGE PHYSICS
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- The potential in a region between x = 0 and x = 6.00 m V = a + bx, where a = 10.0 V and b = -7.00 V/m. Determine (a) the potential at x = 0, 3.00 m, and 6.00 m and (b) the magnitude and direction of the electric field at x = 0, 3.00 m. and 6.00 m.arrow_forwardA constant electric field accelerates a proton from rest through a distance of 2.00 m to a speed of 1.50 105 m/s. (a) Find the change in the protons kinetic energy. (b) Find the change in the systems electric potential energy. (c) Calculate the magnitude of the electric field.arrow_forwardA long thin wire is used in laser printers to charge the photoreceptor before exposure to light. This is done by applying a large potential difference between the wire and the photoreceptor. a. Use Equation 26.23, V(r)=20lnRr to determine a relationship between the electric potential V and the magnitude of the electric field E at a distance r from the center of the wire of radius R (r R). b. Determine the electric potential at a distance of 2.0 mm from the surface of a wire of radius R = 0.80 mm that will produce an electric field of 1.8 106 V/m at that point.arrow_forward
- A proton is located at the origin, and a second proton is located on the x-axis at x = 6.00 fm (1 fm = 10-15 m). (a) Calculate the electric potential energy associated with this configuration. (b) An alpha particle (charge = 2e, mass = 6.64 1027 kg) is now placed at (x, y) = (3.00, 3.00) fm. Calculate the electric potential energy associated with this configuration. (c) Starting with the three-particle system, find the change in electric potential energy if the alpha particle is allowed to escape to infinity while the two protons remain fixed in place. (Throughout, neglect any radiation effects.) (d) Use conservation of energy to calculate the speed of the alpha particle at infinity. (e) If the two protons are released from rest and the alpha panicle remains fixed, calculate the speed of the protons at infinity.arrow_forwardA constant electric field accelerates a proton from rest through a distance of 2.00 m to a speed of 1.50 105 m/s. (a) Find the change in the protons kinetic energy. (b) Find the change in the systems electric potential energy. (c) Calculate the magnitude of the electric field.arrow_forwardIn a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x = 20.0 cm to x = 60.0 cm. (i) Does the electric potential energy of the charge-field system (a) increase, (b) remain constant, (c) decrease, or (d) change unpredictably? (ii) Has the particle moved to a position where the electric potential is (a) higher than before, (b) unchanged, (c) lower than before, or (d) unpredictable?arrow_forward
- Sketch the equipotential lines for the two equal positive charges shown in Figure 19.27. Indicate the direction of increasing potential. Figure 19.27 The electric field near two equal positive charges is directed away from each of the charges.arrow_forwardConsider two conducting spheres with radii R1 and R2 separated by a distance much greater than cither radius. A total charge Q is shared between the spheres. We wish to show that when the electric potential energy of the system has a minimum value, the potential difference between the spheres is zero. The total charge Q is equal to q1 + q2, where q1 represents the charge on the first sphere and q2 the charge on the second. Because the spheres are very far apart, you can assume the charge of each is uniformly distributed over its surface. (a) Show that the energy associated with a single conducting sphere of radius R and charge q surrounded by a vacuum is UE = keq2/2R. (b) Find the total energy of the system of two spheres in terms of the total charge Q, and the radii and R1 and R2. (c) To minimize the energy, differentiate the result to part (b) with respect to q1 and set the derivative equal to zero. Solve for q1 in terms of Q and the radii. (d) From the result to part (c), find the charge q2. (e) Find the potential of each sphere. (f) What is the potential difference between the spheres?arrow_forwardA parallel-plate capacitor has square plates that are 8.00 cm on each side and 3.80 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 8.00 cm on a side and 1.90 mm thick. One slab is Pyrex glass and the other slab is polystyrene. If the potential difference between the plates is 86.0 V, find how much electrical energy can be stored in this capacitor.arrow_forward
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