Chapter 17, Problem 32P

To determine

The voltage across capacitor.

Answer to Problem 32P

The answer is $17.4V$ .

Explanation of Solution

Given:

Charge is $16.5\times {10}^{-8}C$

Capacitance is $9500pF=9.5\times {10}^{-9}F$

Formula used:

It is known that $Q=CV$ , here the amount of charge $Q$ acquired by each plate is proportional to the magnitudes of potential difference $V$ b/w them.

Calculation:

The capacitance is found from $Q=CV\to V=\frac{Q}{C}$

  $=\frac{16.5\times {10}^{-8}C}{9.5\times {10}^{-9}F}=17.4V$

Conclusion:

The required value is $17.4V$ .