Pearson eText Organic Chemistry -- Instant Access (Pearson+)
Pearson eText Organic Chemistry -- Instant Access (Pearson+)
8th Edition
ISBN: 9780135213711
Author: Paula Bruice
Publisher: PEARSON+
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Concept explainers

Lipids
The heterogeneous classes of organic compounds that are not water-soluble but are dissolved in organic solvents that are non-polar in nature are termed lipids. They are a long chain of fatty acids and esters of alcohols. Lipids are generally seen in seve…
Glycerophospholipid
Glycerophospholipid is the most abundantly occuring phospholipids found in the biological membranes. Lipids include a group of organic compounds like fats, hormones, oils, waxes, vitamins etc. They are non-polar molecules and are insoluble in water. Lipi…
Structure Of Camphor
A terpene with the molecular formula of C10H16O is a waxy, white color solid known as camphor. It is flammable. It also possesses a very pungent taste and a strong odor. There are various sources for extracting camphor from natural products such as the …
Glycolipid In Organic Chemistry
Glycolipids are lipids that are an important class of organic compounds in chemistry that have simple to complex applications. They contain carbohydrates, fatty acids, sphingolipids or a glycerol group. In other words, they are the modifications of lipid…
Diterpenoid
The terpenoid class includes diterpenoids, which are chemical compounds with 20 carbon atoms. They are made up of four isoprene units and are derived from geranylgeraniol, a C20 precursor. They have a C20H32 basic structure. These characteristics disting…
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Chapter 17, Problem 83P

A Cannizzaro reaction is the reaction of an aldehyde that has no α-hydrogens with concentrated aqueous sodium hydroxide. In this reaction, half the aldehyde is convened to a carboxylic acid and the other half is converted to an alcohol. Propose a mechanism for the following Cannizzaro reaction:

Chapter 17, Problem 83P, A Cannizzaro reaction is the reaction of an aldehyde that has no -hydrogens with concentrated

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Chapter 17 Solutions

Pearson eText Organic Chemistry -- Instant Access (Pearson+)

Ch. 17.1 - Prob. 1PCh. 17.1 - Prob. 2PCh. 17.1 - Prob. 3PCh. 17.1 - Prob. 4PCh. 17.1 - Rank the compounds in each of the following groups...Ch. 17.2 - Explain why 92% of 2,4-pemtanedione exists as the...Ch. 17.3 - Draw the enol tautomers for each of the following...Ch. 17.3 - Prob. 8PCh. 17.4 - Prob. 9PCh. 17.4 - Prob. 10P
Ch. 17.5 - Show how the following compounds can be prepared...Ch. 17.6 - What compound is formed when a dilute solution of...Ch. 17.7 - Prob. 13PCh. 17.7 - Prob. 14PCh. 17.7 - How many stereoisomers are obtained from each of...Ch. 17.7 - Prob. 16PCh. 17.8 - Prob. 17PCh. 17.9 - Prob. 18PCh. 17.9 - What reagents should be used to prepare the...Ch. 17.10 - Prob. 20PCh. 17.10 - What aldehyde or ketone would be obtained when...Ch. 17.11 - Prob. 22PCh. 17.11 - How could you prepare the following compound using...Ch. 17.12 - Prob. 25PCh. 17.12 - What two carbonyl compound are required for the...Ch. 17.12 - Propose a mechanism for the following reaction:Ch. 17.13 - Draw the products of the following reactions:Ch. 17.13 - Prob. 29PCh. 17.13 - Prob. 30PCh. 17.14 - Prob. 31PCh. 17.15 - Write the mechanism for the reaction of a...Ch. 17.15 - Prob. 33PCh. 17.15 - Prob. 34PCh. 17.15 - Draw the product of the reaction of each of the...Ch. 17.16 - Draw the product obtained by heating each pair of...Ch. 17.16 - What two carbonyl compounds are needed to...Ch. 17.17 - Prob. 38PCh. 17.18 - Prob. 39PCh. 17.18 - Prob. 40PCh. 17.19 - Prob. 41PCh. 17.20 - Prob. 43PCh. 17.21 - Propose a mechanism for the formation of...Ch. 17.21 - Prob. 45PCh. 17.21 - a. If the biosynthesis of palmitic acid were...Ch. 17.21 - Prob. 47PCh. 17 - Prob. 48PCh. 17 - Prob. 49PCh. 17 - Number the following compounds in order of...Ch. 17 - The 1H NMR chemical shifts of nitromethane,...Ch. 17 - Prob. 52PCh. 17 - Draw the products of the following reactions: a....Ch. 17 - A racemic mixture of 2-methyl-1-phenyl-1-butanone...Ch. 17 - Draw the products of the following reaction:Ch. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - In the presence of excess base and excess halogen,...Ch. 17 - Identify A-L. (Hint: A shows three singles in its...Ch. 17 - Using cyclopentanone as the reactant, show the...Ch. 17 - Show how 4-methyl-3-hexanol can be synthesized...Ch. 17 - Show how the following compound can be synthesized...Ch. 17 - Show how the following compounds can be prepared...Ch. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Indicate how each of the following compounds can...Ch. 17 - Prob. 67PCh. 17 - The ketone whose 1H NMR spectrum is shown here was...Ch. 17 - Indicate how the following compounds can be...Ch. 17 - Compound A with molecular formula C6H10 has two...Ch. 17 - Prob. 71PCh. 17 - Draw the products of the following reactions:Ch. 17 - Prob. 73PCh. 17 - a. Show how the amino acid alanine can be...Ch. 17 - Show how the following compounds can be...Ch. 17 - Prob. 76PCh. 17 - Explain why the following bromoketone forms...Ch. 17 - Prob. 78PCh. 17 - A carboxylic arid is formed when an -haloketone...Ch. 17 - An , -unsaturated carbonyl compound can be...Ch. 17 - What carbonyl compounds are required to prepare a...Ch. 17 - Prob. 82PCh. 17 - A Cannizzaro reaction is the reaction of an...Ch. 17 - Propose a mechanism for each of the following...Ch. 17 - The following reaction is known as the benzoni...Ch. 17 - Prob. 86PCh. 17 - Prob. 87PCh. 17 - Prob. 88PCh. 17 - Prob. 89PCh. 17 - Prob. 90PCh. 17 - Propose a mechanism for the following reaction:Ch. 17 - What reagents are required to convert the reactant...Ch. 17 - Starting with bromocyclohexane, how can each of...Ch. 17 - Describe how the following compounds can be...Ch. 17 - Prob. 4PCh. 17 - Describe three ways to synthesize the following...Ch. 17 - Explain why 92% of 2.4-pentanedione exists as the...Ch. 17 - Describe how the following compound can be...Ch. 17 - Prob. 8PCh. 17 - Prob. 9PCh. 17 - Prob. 10PCh. 17 - Show how the following compounds can be...
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Lipids - Fatty Acids, Triglycerides, Phospholipids, Terpenes, Waxes, Eicosanoids; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=7dmoH5dAvpY;License: Standard YouTube License, CC-BY