BROOKER BIOLOGY
5th Edition
ISBN: 9781307656152
Author: BROOKER
Publisher: MCG/CREATE
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Textbook Question
Chapter 17, Problem 9TY
Genes located on a sex chromosome are said to be
- a. X-linked.
- b. dominant.
- c. hemizygous.
- d. sex-linked.
- e. autosomal
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For each of the following chromosome complements, what is the phenotypic sex of a person who has a. XY with the SRY gene deleted? b. XX with a copy of the SRY gene on an autosomal chromosome? c. XO with a copy of the SRY gene on an autosomal chromosome? d. XXY with the SRY gene deleted? e. XXYY with one copy of the SRY gene deleted?
Which of the following is not a characteristic of X-linked recessive traits in humans?
a.
Approximately one-half of the sons of a female carrier are affected.
b.
More males than females affected.
c.
Phenotypically normal daughters of affected men are always carriers.
d.
They cannot be passed from father to son.
e.
Affected daughters always have an affected mother.
Fragile X syndrome is an X-linked recessive Achondroplasia is an autosomal dominant trait characterized by a shortened stature. An XX individual is a carrier for Fragile X disorder and is unaffected by achondroplasia. An XY individual is not affected by Fragile X disorder and has achondroplasia.
a. What is the XX individual’s genotype
b. What is the XY individual’s genotype?
c. If the two individuals where to have children, what are the possible genotypes and phenotypes of their children? Use a Punnett square.
d. What is the probability of them having a child with Fragile X and achondroplasia?
Chapter 17 Solutions
BROOKER BIOLOGY
Ch. 17.1 - Prob. 1CCCh. 17.1 - Prob. 2CCCh. 17.1 - Prob. 3CCCh. 17.1 - Prob. 4CCCh. 17.1 - Mendels Laws of Inheritance Concept Check: What...Ch. 17.2 - Prob. 1CSCh. 17.2 - Prob. 2CSCh. 17.2 - Prob. 1CCCh. 17.3 - Prob. 1CCCh. 17.3 - Prob. 2CC
Ch. 17.4 - Prob. 1CCCh. 17.4 - Prob. 1EQCh. 17.4 - Prob. 2EQCh. 17.4 - Prob. 3EQCh. 17.5 - Prob. 1CSCh. 17.5 - Prob. 1CCCh. 17.6 - Prob. 1CCCh. 17 - Prob. 1TYCh. 17 - During which phase of nuclear division does the...Ch. 17 - Prob. 3TYCh. 17 - Which of Mendels laws cannot be observed in a...Ch. 17 - During a __________blank, an individual with the...Ch. 17 - Prob. 6TYCh. 17 - Prob. 7TYCh. 17 - A hypothetical flowering plant species produces...Ch. 17 - Genes located on a sex chromosome are said to be...Ch. 17 - Prob. 10TYCh. 17 - Prob. 1CQCh. 17 - A cross is made between individuals having the...Ch. 17 - Core Concept: Systems We can view life as a...Ch. 17 - Discuss the principles of the chromosome theory of...Ch. 17 - When examining a human pedigree, what patterns do...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Which of the below explains why trisomy is better tolerated in humans than monosomy? (Select all correct options). a. Loss of heterozygosity in monosomy b. Increased gene expression in trisomic cells is beneficial c. Reduced gene expression in monosomy d.The extra chromosome in trisomic cells is degraded Which two are both necessary to hold a tetrad together until Anaphase I? a) nondisjunction b) cross over c) centromere cohesion d) synaptonemal complex e) separese activityarrow_forwardConsider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?arrow_forwardExplain why a person with Klinefelter Syndrome (XXY) still exhibits abnormal phenotypes despite the fact that one of the extra X Chromosome is inactivated practically leaving an XY active sex chromosomes similar to a normal male?arrow_forward
- Color blindness in humans is an X-linked recessive trait. This means that... O a. Females are more likely to be color blind than males b. The gene associated with color blindness is found on the X chromosome, and an individual must have one (in males) or two (in females) mutant copies of the allele in order to be diagnosed as being color blindarrow_forwardWhich of the following statements is FALSE? Inactivation of one of the two X chromosomes in the somatic cells of mammalian females..... a. underlies the Calico phenotype in cats. b. leads to cellular mosaicism in females heterozygous for an X-linked gene. c. affects 75 % of the paternal and 25 % of the maternal X-chromosomes of a mammalian body. d. leads to the formation of a Barr body in female cells' nuclei. e. is the mechanism in mammals to compensate for the higher dosage of X-linked genes in females as compared to males.arrow_forwardWhen the phenotype of the offspring is determined by endoparasites in the father it is… a. epistasis b. due to genes located in the mitochondria. c. a maternal effect d. non-nuclear inheritance e. a non-additive genetic effectarrow_forward
- In a karyotype of a man whose wife has had several miscarriages, it was discovered that he had onlv 45 chromosomes. However, he displayed no obvious phenotypic defects. Furthermore, one of the chromosomes of pair 15 was abnormally long. Which of the following terms best describes the condition of this man? a. monosomy b,. trisomy c. tetrasomy d. translocation carrier e. edward syndormearrow_forwardWhich of the following statements is TRUE? Overexpression of the X-chromosome in the somatic cells of males a. leads to the formation of a Barr body in male cells' nuclei. b. leads to cellular mosaicism in males hemizygous for an X-linked gene. c. is characteristic of all XY systems of sex determination. d. is the mechanism in flies to compensate for the higher dosage of X-linked genes in females as compared to males. e. None of the abovearrow_forwardColor blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?arrow_forward
- Hemophilia is an X-linked recessive phenotype. Suppose a man who expresses the hemophilia phenotype has children with a woman who has the normal phenotype (and does not have a family history of hemophilia). If the couple have a son, what are the chances that he will have hemophilia? A) 50% B) 25% C) 0% D) 100%arrow_forwardHemophilia is another example of an X-linked disease caused when a recessive allele (Xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? Will any of their daughters develop hemophilia?arrow_forwardNow assume that the pedigree shown in question 1 shows the inheritance of a rare genetic disease. a) The disease is most likely autosomal dominant b) The disease is most likely autosomal recessive c) The disease is equally likely to be either autosomal dominant or autosomal recessive, but cannot be x-linked d) Cannot be determined from the information givenarrow_forward
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