Concept explainers
(a)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have
The sugars that have a free carbonyl group are called reducing sugars.
(b)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
(c)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
(d)
Interpretation: The term monosaccharide, disaccharide, reducing sugar, anomers, enantiomer and aldohexoses whether applies to both the members of the given pair or not has to be stated.
Concept introduction: Monosaccharides are those type of sugars which cannot be hydrolysed further.
Disaccharides are those type of sugars which have two units of monosaccharides.
The enantiomers are the molecules that form non-superimposable mirror images of each other.
Carbon atom which behaves as a stereocenter in the cyclic form of the hemiacetal compound is known as anomeric carbon. The molecule containing the anomeric carbon is called anomer.
The monosaccharides that have aldehyde as a functional group and a long chain of six carbon atoms are called aldohexoses.
The sugars that have a free carbonyl group are called reducing sugars.
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Chapter 18 Solutions
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
- Identify the name of each of the structures of sugar and identify as reducing or nonreducing sugar. One of the structures may be not identified from the usual structures of disaccharides. Kindly answer a, b, c, and d.You only identify the name of each structure of sugars and identify as reducing or nonreducing sugar. No explanation needed.arrow_forwardRefer to the figure below. Determine whether the given descriptions between the relationship of glucose and galactose is correct or incorrect. * сно ÇHO H OH HO-H H- -OH HO-H HO H- H-OH ČH,OH D-Glucose -H -OH H- -он CH,OH D-Galactose CORRECT INCORRECT Glucose and galactose are both Aldohexoses They constitute the structure of the disaccharide maltose They are epimers at carbon 4 They are not mirror images of each other, neither an enantiomeric pairarrow_forwardDescribe the structural similarities and differences of the following pairs. Identify which of these is a structural isomer, and how to identify structural isomers. a. Glucose and Mannose b. Galactose and Fructose c. Ribulose and Xylulose d. ribose and glucosearrow_forward
- Consider the following statements: (1) The term sugar is a general designation for both monosaccharides and disaccharides. (2) The "penultimate carbon" in a monosaccharide is used to determine D- or L-configuration. (3) Sucrose is a reducing sugar and lactose is a nonreducing sugar. O Two of the three statements are true. All three statements are true. O Only one of the statements is true. None of the statements are true.arrow_forwardConstruct the two enantiomeric forms/structure of the following monosaccharides and designate the handedness of each using D, L system: a. Ribulosearrow_forwardPage 3 of 6 Previous Next For items 16-20, determine the monosaccharide units for each carbohydrate. Choic are: A. B-D-galactopyranose, and D-glucopyranose B. a-D-glucopyranose and D-glucopyranose C. N-acetyl-galactosamine D. B-D-glucuronate-2-sulfate, E. N-acetyl-B-D-glucosamine, and D-glucuronate 16. Maltose 17. Lactose and N-sulfo-D-glucosamine-6-sulfate 18. A-antigen oligosaccharide (end unit) 19. Heparin 20. Hyaluronic acid 344arrow_forward
- Consider the trisaccharide below and answer the following questions: но. OH OH H. OH HO Но ОН ÓH H ÓH ОН C Name of monosaccharide A (Follow this format in typing your answer: ribose): Name the glycosidic linkage between monosaccharides A and B. (strictly follow this format, do not put spaces in between: beta-1,2): Is the trisaccharide a reducing sugar? Type Yes or No: I- I-arrow_forwardDraw the Fischer projection formula for each sugar and give the importance/use of each. 1. D- glyceraldehyde 2. D- erythrose 3. D- ribose 4. D- deoxyribose 5. D- glucose 6. D- galactose 7. D- fructose 8. D- ribulosearrow_forwardA trisaccharide was isolated from a new species of red algae. The sample was hydrolyzed and monosaccharide units were analyzed in different colorimetric tests. Based on the data below, what are the identity of monosaccharide A, B, and C? A= fructose, B=mannose, C=xylose A= xylose, B=mannose, C= fructose A = mannose, B= fructose, C=xylose A= xylose, B= fructose, C=galactose A=galactose, B= fructose, C=xylose A=xylose, B= fructose, C=mannose A= fructose, B= xylose, C=galactose A=galactose, B=xylose, C=fructosearrow_forward
- Identify which of the following structural polysaccharides (amylopectin, amylose, glycogen, cellulose, and chitin) fits the description given below. A specific description may apply to more than one of the polysaccharides. 1. Contains both a(1→4) and a(1→6) glycosidic linkages 2. Polymer chain is unbranched 3. Glucose derivatives are present in the polymer chain 4. Contains only ß(1→4) glycosidic linkagesarrow_forwardListed below are descriptions that may belong to amylose, amylopectin, both, or it may not belong to either. Write A if it describes amylose, B if it describes amylopectin, AB if the statement applies to both, or O if it doesn’t apply to either. 1. Its monosaccharides are bound by at least one α-1,4-glycosidic bond. 2. It contains α-1,6-glycosidic bonds. 3. It can be broken down by the enzyme α-amylase. 4. A polysaccharide made up of gulose. 5. It can form a double helix.arrow_forwardDraw the Fischer projection formula for each sugar and give the importance/use of each. D- deoxyribose D- glucose D- galactose D- fructose D- ribulosearrow_forward
Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College