EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 18, Problem 18.66AP
Interpretation Introduction
(a)
Interpretation:
The oxidation state of iron in the protoporphyrin
Concept introduction:
The oxidation state of the metal represents the tendency of the metal to lose electrons. More the tendency to donate electrons higher will be the oxidation state. The
Interpretation Introduction
(b)
Interpretation:
The total electron count around the iron metal in the protoporphyrin
Concept introduction:
The electron count of the metal is the number of electrons present in the bonding molecular orbital of the metal. The electrons donated by the ligand also contribute in the electron count.
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(9)(Inorganic) SbCl3 is a white solid that must be protected from water, as it reacts immediately to form oxychlorides. With donor ligands such as amines, it forms adducts of the SbCl3.2L type. In contrast, SbI3 is deep red in color, likewise, although more slowly, it hydrolyzes with water. When it forms compounds of the Sbl3.2L type with amines, the color disappears. Compare and explain these observations.
(a) How would you account for the following:
(i) Actinoid contraction is greater than lanthanoid contraction.
(ii) Transition metals form coloured compounds.
2.) Phosphorus in urine can be determined by treating with molybdenum(VI) and then reducing the
phosphomolybdate with aminonaphthol sulfonic acid to give the characteristic molybdenum blue color.
This absorbs at 690 nm. A patient excreted 1270mL urine in 24 h, and the pH of the urine was 6.5. A
1.00-ml aliquot of the urine was treated with molybdate reagent and aminonaphthol sulfonic acid and
was diluted to a volume of 50.0 ml. A series of phosphate standards was similarly treated. The
absorbance of the solutions at 690 nm, measured against a blank, were as follows:
Solution
Absorbance
1.00 ppm P
2.00 ppm P
0.205
0.410
3.00 ppm P
0.615
4.00 ppm P
0.820
Urine sample 0.625
(a) Calculate the number of grams of phosphorus excreted per day.
(b) Calculate the phosphate concentration in the urine as millimoles per liter.
(c) Calculate the ratio of HPO, to H,PO, in the sample:
K= 1.1 x 10
K,= 7.5 x 10+
K,= 4.8 x 10-
Chapter 18 Solutions
EBK ORGANIC CHEMISTRY
Ch. 18 - Prob. 18.1PCh. 18 - Prob. 18.2PCh. 18 - Prob. 18.3PCh. 18 - Prob. 18.4PCh. 18 - Prob. 18.5PCh. 18 - Prob. 18.6PCh. 18 - Prob. 18.7PCh. 18 - Prob. 18.8PCh. 18 - Prob. 18.9PCh. 18 - Prob. 18.10P
Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Prob. 18.13PCh. 18 - Prob. 18.14PCh. 18 - Prob. 18.15PCh. 18 - Prob. 18.16PCh. 18 - Prob. 18.17PCh. 18 - Prob. 18.18PCh. 18 - Prob. 18.19PCh. 18 - Prob. 18.20PCh. 18 - Prob. 18.21PCh. 18 - Prob. 18.22PCh. 18 - Prob. 18.23PCh. 18 - Prob. 18.24PCh. 18 - Prob. 18.25PCh. 18 - Prob. 18.26PCh. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Prob. 18.29PCh. 18 - Prob. 18.30PCh. 18 - Prob. 18.31PCh. 18 - Prob. 18.32PCh. 18 - Prob. 18.33PCh. 18 - Prob. 18.34PCh. 18 - Prob. 18.35PCh. 18 - Prob. 18.36PCh. 18 - Prob. 18.37PCh. 18 - Prob. 18.38PCh. 18 - Prob. 18.39PCh. 18 - Prob. 18.40PCh. 18 - Prob. 18.41PCh. 18 - Prob. 18.42PCh. 18 - Prob. 18.43PCh. 18 - Prob. 18.44PCh. 18 - Prob. 18.45PCh. 18 - Prob. 18.46APCh. 18 - Prob. 18.47APCh. 18 - Prob. 18.48APCh. 18 - Prob. 18.49APCh. 18 - Prob. 18.50APCh. 18 - Prob. 18.51APCh. 18 - Prob. 18.52APCh. 18 - Prob. 18.53APCh. 18 - Prob. 18.54APCh. 18 - Prob. 18.55APCh. 18 - Prob. 18.56APCh. 18 - Prob. 18.57APCh. 18 - Prob. 18.58APCh. 18 - Prob. 18.59APCh. 18 - Prob. 18.60APCh. 18 - Prob. 18.61APCh. 18 - Prob. 18.62APCh. 18 - Prob. 18.63APCh. 18 - Prob. 18.64APCh. 18 - Prob. 18.65APCh. 18 - Prob. 18.66APCh. 18 - Prob. 18.67APCh. 18 - Prob. 18.68APCh. 18 - Prob. 18.69APCh. 18 - Prob. 18.70APCh. 18 - Prob. 18.71APCh. 18 - Prob. 18.72APCh. 18 - Prob. 18.73APCh. 18 - Prob. 18.74APCh. 18 - Prob. 18.75APCh. 18 - Prob. 18.76APCh. 18 - Prob. 18.77APCh. 18 - Prob. 18.78APCh. 18 - Prob. 18.79APCh. 18 - Prob. 18.80APCh. 18 - Prob. 18.81APCh. 18 - Prob. 18.82APCh. 18 - Prob. 18.83APCh. 18 - Prob. 18.84APCh. 18 - Prob. 18.85APCh. 18 - Prob. 18.86APCh. 18 - Prob. 18.87APCh. 18 - Prob. 18.88APCh. 18 - Prob. 18.89APCh. 18 - Prob. 18.90APCh. 18 - Prob. 18.91APCh. 18 - Prob. 18.92AP
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