Biology: The Dynamic Science (MindTap Course List)
Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
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Chapter 18, Problem 1TYK
Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer
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Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

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Students have asked these similar questions
Describe What are the sticky ends of the restriction fragments? Select one: a. The surfaces of sticky ends contain matching base pairs, allowing fragments to splice. b. The surfaces of sticky ends have glue like substance that allow fragments to splice. c. The surfaces of sticky ends contain the exact same nucleotides, allowing fragments to bond. d. The surfaces of sticky ends have velcro like structure, allowing fragments to bond.
Arrange the following steps in the sequence they would happen in a DNA cloning experiment. a. sealing DNA fragments into vectors with DNA ligase; b. utilizing a probe to detect a clone in the library; c. sequencing the clone's DNA; d. creating a DNA library of clones; e. cutting genomic DNA with restriction enzymes.   A. e,a,d,b,c   B. a,d,b,c,e   C. c,b,e,a,d   D. e,d,a,c,b
What is the enzymatic function of restriction enzymes? Group of answer choices a. to cut nucleic acids at specific sites b. to join nucleotides during transcription c. to add new nucleotides to the growing strand of DNA d. to repair breaks in sugar - phosphate backbones
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