The total work done by the gas and heat absorbed by gas in each portion of cycle.
Answer to Problem 76P
The total work done is
Explanation of Solution
Given:
The initial pressure is
The temperature is
Formula used:
The expression for volume at D is given by,
The expression for pressure at point C is given by,
The expression for temperature at point A and B is given by,
The expression for heat absorbed at D is given by,
The expression for heat absorbed at A is given by,
The expression for heat absorbed at B is given by,
The expression for heat absorbed at C is given by,
The expression for total work done is given by,
Calculation:
The volume at point D is calculated as,
The pressure at point C is calculated as,
The temperature at point A and B is calculated as,
The heat absorbed at point D is calculated as,
The heat absorbed at point A is calculated as,
The heat absorbed at point B is calculated as,
The heat absorbed at point C is calculated as,
The total work done is calculated as,
Conclusion:
Therefore, the total work done is
Want to see more full solutions like this?
Chapter 18 Solutions
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
- 1.50 mol of an ideal gas with a constant ratio of heat capacities at constant pressure and volume y =2 = 1.40 is taken through the (reversible) cycle shown in the figure below. The process A - B is an expansion at constant temperature, whereas B →C and C → A are constant-pressure compression and constant-volume processes, respectively. 040 a) What is the temperature TA of the gas at A? P (atm) For the cycle as a whole, Isothermal b) calculate the (net) work done W (by the gas), 04021 c) calculate the (total) heat transfer Q, process d) find the change in the (internal) energy U of the gas, B e) verify that the 1" law of thermodynamics C is satisfied. 1 liter=1.00x10 m , 1 atm=1.01x105 N/m² , kɛ = 1.38x1023 J/K , NA=6.02x1023 mol. -V (liters) 50 10arrow_forwardOnly d-f pleasearrow_forwardNeeds Complete typed solution with 100 % accuracy.arrow_forward
- A heat engine takes 3 moles of an ideal gas through the reversible cycle abca, on the pV diagram shown in the figure. The path bc is an isothermal process. The temperature at c is 700. K, and the volumes at a and c are 0.020 m3 and 0.25 m3, respectively. The molar heat capacity at constant volume, of the gas, is 20 J/mol·K, and the ideal gas constant is R = 8.314 J/(mol∙K). What is the thermal efficiency of this engine?arrow_forwardIdentify the processes in the cycle. Þ 1. Path AB = The temperature in (1) is 350 K, the work done in (2) is 7.0 J with no heat applied/released, and the pressure in (3) is 3 atm. The change in internal energy in (5) is 12.0 J (with no heat applied or released). 2. Path BC = 3. Path CD= 4. Path DE= D 5. Path EA = V 6. What is the change in internal energy of the (ideal) gas along path (3) in joules? *Indicate whether the process is compression or expansion, e.g. isobaric expansion, etc.arrow_forwardThe heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If I mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule.arrow_forward
- An ideal gas is taken from a to b on the pV diagram shown in the figure. During this process, 700 J of heat is added and the pressure doubles. (a) How much work is done by or on the gas? Explain. (b) How does the temperature of the gas at a compare to its temperature at b? Be specific. (c) How does the internal energy of the gas at a compare to the internal energy at b? Be specific and explain.arrow_forward0.5 mole of an ideal monatomic gas starts from 500 point a in the diagram to the right. It undergoes a a b 400 constant pressure expansion from a to b; a constant volume compression from b to c: and an isothermal a200 compression from c to a. 200 From last week, find the three temperature values Ta, To and T. and the total work for one cycle W. Now find the heat added along the three processes 100 Qab, Qbc and Qca and the efficiency of this process. 2 4 Find the change in entropy along each process Sabı Spc and Sca and the total entrophy change. volume (m³) pressure (Pa)arrow_forwardA heat engine using 1.0 mol of a monatomic gas follows the cycle shown. 3750 J of heat energy is transferred to the gas during process 1→2. Determine Wsys, Q, and ΔEth for each of the four processes in this cycle. What is the thermal efficiency of this heat engine?arrow_forward
- The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note Note that 1 literxatmosphere is equal to 101.325 joule. Sol": given Heat of melting ice at 1 atm pressure = 1.4363 kca kcal/ 2 = 1.4363 kcal/mole mole volume of ice = 0·0196 lts " water = 0.018 lts @ work done is define as w=pdv » w = P(V₁ hot W = 1 (0·018-00196) W = 0·0016 Cal Pay Kat Ansarrow_forward"Two moles of an ideal monatomic gas go through cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Process ab is isobaric while process bc is isochoric.Ta = 200 K and Tb = 300 K. What is the work for process ca?"arrow_forwardSP 2P AT Q1 Q= 6 D 2V, Q A 1.00-mol sample of a monatomic ideal gas is taken through the cycle shown. At point A, the pressure, volume, and temperature are P₁ = 0.6 atm, V₁ = 1.8 m³, and T₁, respectively. Find the efficiency of an engine operating in this cycle. Write your efficiency in decimal form and round your answer to the nearest hundredth (i.e. if your efficiency is 0.867, round it to 0.87). Take 1 atm = 101300 Pa.arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning