Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)
8th Edition
ISBN: 9780135213759
Author: John McMurry, David Ballantine
Publisher: PEARSON+
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Textbook Question
Chapter 19, Problem 19.48AP
What is the difference between the lock-and-key model of enzyme action and the induced-fit model?
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[S]
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Chapter 19 Solutions
Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)
Ch. 19.1 - Prob. 19.1PCh. 19.1 - The enzyme LDH converts lactate to pyruvate. In...Ch. 19.2 - The cofactors NAD+, Cu2+, Zn2+, coenzyme A, FAD,...Ch. 19.3 - Describe the reactions that you would expect these...Ch. 19.3 - Prob. 19.5PCh. 19.3 - Prob. 19.6PCh. 19.3 - Prob. 19.7PCh. 19.3 - Prob. 19.8PCh. 19.4 - Prob. 19.9KCPCh. 19.5 - Prob. 19.10KCP
Ch. 19.5 - Prob. 19.11PCh. 19.5 - Prob. 19.12PCh. 19.6 - Prob. 19.13PCh. 19.6 - Prob. 19.14PCh. 19.7 - (a) L-Threonine is converted to L-isoleucine in a...Ch. 19.8 - AZT (zidovudine) inhibits the synthesis of the HIV...Ch. 19.8 - Prob. 19.3CIAPCh. 19.8 - Prob. 19.16PCh. 19.9 - Does the enzyme described in each of the following...Ch. 19.9 - Prob. 19.18PCh. 19.9 - Compare the structures of vitamin A and vitamin C....Ch. 19.9 - Prob. 19.20PCh. 19.9 - Prob. 19.21KCPCh. 19.9 - Prob. 19.22PCh. 19.9 - Prob. 19.4CIAPCh. 19.9 - Prob. 19.6CIAPCh. 19.9 - Prob. 19.7CIAPCh. 19.9 - Enzyme levels in blood are often elevated in...Ch. 19.9 - Prob. 19.9CIAPCh. 19.9 - Prob. 19.23PCh. 19 - Prob. 19.24UKCCh. 19 - Prob. 19.25UKCCh. 19 - Prob. 19.26UKCCh. 19 - Prob. 19.27UKCCh. 19 - Prob. 19.28APCh. 19 - Explain how the following mechanisms regulate...Ch. 19 - Prob. 19.30APCh. 19 - Prob. 19.31APCh. 19 - Prob. 19.32APCh. 19 - Prob. 19.33APCh. 19 - Prob. 19.34APCh. 19 - Prob. 19.35APCh. 19 - Prob. 19.36APCh. 19 - Prob. 19.37APCh. 19 - Name an enzyme that acts on each molecule. (a)...Ch. 19 - Name an enzyme that acts on each molecule. (a)...Ch. 19 - What features of enzymes make them so specific in...Ch. 19 - Describe in general terms how enzymes act as...Ch. 19 - Prob. 19.42APCh. 19 - Prob. 19.43APCh. 19 - Prob. 19.44APCh. 19 - Prob. 19.45APCh. 19 - Prob. 19.46APCh. 19 - Prob. 19.47APCh. 19 - What is the difference between the lock-and-key...Ch. 19 - Why is the induced-fit model a more likely model...Ch. 19 - Prob. 19.50APCh. 19 - Prob. 19.51APCh. 19 - How do you explain the observation that pepsin, a...Ch. 19 - Prob. 19.53APCh. 19 - Prob. 19.54APCh. 19 - Prob. 19.55APCh. 19 - Prob. 19.56APCh. 19 - Prob. 19.57APCh. 19 - The text discusses three forms of enzyme...Ch. 19 - Prob. 19.59APCh. 19 - Prob. 19.60APCh. 19 - Prob. 19.62APCh. 19 - Prob. 19.63APCh. 19 - The meat tenderizer used in cooking is primarily...Ch. 19 - Prob. 19.65APCh. 19 - Why do allosteric enzymes have two types of...Ch. 19 - Prob. 19.67APCh. 19 - Prob. 19.68APCh. 19 - Prob. 19.69APCh. 19 - Prob. 19.70APCh. 19 - Prob. 19.71APCh. 19 - Prob. 19.72APCh. 19 - Prob. 19.73APCh. 19 - Prob. 19.74APCh. 19 - Prob. 19.75APCh. 19 - Prob. 19.76APCh. 19 - Prob. 19.77APCh. 19 - Prob. 19.78APCh. 19 - Prob. 19.79APCh. 19 - Prob. 19.80CPCh. 19 - Prob. 19.81CPCh. 19 - Prob. 19.82CPCh. 19 - Prob. 19.83CPCh. 19 - Prob. 19.84CPCh. 19 - Prob. 19.85CPCh. 19 - Prob. 19.86CPCh. 19 - Prob. 19.87CPCh. 19 - Prob. 19.88GPCh. 19 - The ability to change a selected amino acid...Ch. 19 - Prob. 19.90GPCh. 19 - Prob. 19.91GP
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- What is the defining characteristic for an enzyme catalyzing a sequential reaction? A doubledisplacement reaction?arrow_forwardWhat is the difference between lock-and-key and induced-fit models for binding of a substrate to an enzyme?arrow_forwardWhat is the relationship between a transitionstate analog and the induced-fit model of enzyme kinetics?arrow_forward
- Under the following conditions, fill in the blanks. Then, describe why this inhibitor is the type of inhibitor you identified it as. If you were to add 5nM of a reversible inhibitor, the Km for the measured enzyme catalyzed reaction would ______ (Increase, Decrease, Stay the same) to ______µM (choose appropriate value) and Vmax would _______ (Increase, Decrease, Stay the same) to ______µMs-1. So, this inhibitor is a ______ (Competitive, Uncompetitive, Mixed) inhibitor. Conditions: kcat = 130 s^-1 Vo = 3.0 μMs-1 S = 10 μM Et = 0.09 µMarrow_forwardThe Lineweaver-Burke plot was originally developed in order to "linearize" the data obtained from enzyme kinetics experiments, in order to facilitate the determination of kinetic parameters. Why is it not considered to be an accurate method for this purpose? It is very difficult to draw a straight line on a computer. It is very difficult to calculate the variables required for the "x" and "y" axis. It is more accurate to use the standard "V versus [S]" plot to determine Vmax and KM- The plot weights the least accurate data points the most heavily. It is no longer considered to be acceptable to extrapolate from known data.arrow_forwardwhat is the purpose of staggering the start and stop of the reactions? With reference to your experimental protocol, what is the purpose of staggering the start and stop of the reactions? A.To ensure that the reaction occurs with different amounts of enzyme in each tube so as to ensure comparability between reaction tubes. B.To ensure that the reaction occurs at exactly the same pH in each tube so as to ensure comparability between reaction tubes. C.To ensure that the reaction occurs for exactly the same time interval (30 minutes) in each tube so as to ensure comparability between reaction tubes. D.To ensure that the reaction occurs with exactly the same amount of substrate in each tube so as to ensure comparability between reaction tubes.arrow_forward
- How is the Michaelis constant defined, and what does a low or high value for Km tell you? What is the difference between the velocity and initial velocity of an enzyme reaction? What determines the efficiency of an enzyme reaction, and what terms are used to describe it?arrow_forwardConsider these three sketches: B A HHHH A A Which sketches represent the action of an enzyme? Check none of them if none of them do. And finally, for that same sketch, what is C? B |HH| For that same sketch, what is B? Again your answer should be a word or very short phrase. A B If you said at least one sketch represents the action of an enzyme, for the first sketch that does, what is A? Your answer should be a word or very short (two- or three-word) phrase. 3000|| 3 3 O (none of them) 0 0 Xarrow_forwardThe initial velocities of two different enzyme-catalyzed reactions were measured over a series of substrate concentrations. The following results were obtained: Enyme A: KM = 1.5 mM, Vmax = 10 μM s-1 Enyme B: KM = 5.0 mM, Vmax = 85 µM s-1 (a) Which enzyme binds to its substrate more tightly (assume k.1 >> k₂ in the Michaelis-Menten model)? (b) Calculate the initial velocities of each reaction when the substrate concentration is 2.5 mM. (c) Calculate the Kcat of each enzyme if the total enzyme concentration is 100 nM. (d) Which enzyme is the more efficient catalyst? Explain your answer. The enzyme carbonic anhydrase is strongly inhibited by the drug acetazolamide. A plot of the initial reaction velocity (as a percentage of Vmax) in the absence and presence of the inhibitor is shown below. What type of inhibition is taking place? Explain your reasoning. V (% of Vmax) 100 50 0.2 0.4 No inhibitor Acetazolamide [S] (MM) 0.6 0.8 1arrow_forward
- The following data was obtained during kinetic analysis of an enzyme with and without an inhibitor. Substrate concentration (mM) Reaction rate without inhibitor (µM/s) Reaction rate with inhibitor (µM/s) 10 28 12 20 50 23 40 83 42 60 107 58 100 139 83 200 179 125 300 197 150 400 209 167 560 227 197 How do you calculate the KM for the enzyme in the absence of an inhibitor. And how do you calculate kcat with the given enzymatic concentration of 5 µM.arrow_forwardIn the scheme below which represents the mechanism of action for a large number of enzymes: A+B⟺AB⟶C The steady state approximation is reached when: d[AB]/dt≈0 k2≫k1 k−1≫k1 k−1=k1arrow_forwardYou have obtained experimental kinetic data for two versions of the same enzyme, a wild‑type and a mutant differing from the wild‑type at a single amino acid. The data are given in the table. Compare the kinetic parameters of the two versions using the data in the table. Assuming a two-step reaction scheme in which ?−1 is much larger than ?2, which of the following statements are correct? The mutant version has a higher affinity for the substrate. The wild‑type version requires a greater concentration of substrate to achieve ?maxVmax. The wild‑type version has a higher affinity for the substrate. The mutant version requires a greater concentration of substrate to achieve ?maxVmax. Calculate the initial velocity of the reaction catalyzed by the wild‑type enzyme when the substrate concentration is 10 mM. The reaction equilibrium is reached once there is no net change in the concentration of the substrate or the product. Based on the data table and your initial…arrow_forward
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