Chemistry: An Atoms-Focused Approach
Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
Question
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Chapter 19, Problem 19.70QA
Interpretation Introduction

To find:

a) The fuel values of gaseous benzene and acetylene gas based on the thermochemical data in Appendix 4.

b) Whether one mole of benzene has higher or lower fuel value than three moles of acetylene

Expert Solution & Answer
Check Mark

Answer to Problem 19.70QA

Solution:

a) Fuel value of benzene is  42.26kJg, and fuel value of acetylene is 49.91 kJ/g

b) One mole of benzene has a lower fuel value than three mole acetylene.

Explanation of Solution

1) Concept:

Fuel value is the quantity of energy released during the complete combustion of one gram of a substance.  To calculate the fuel value of the compound, we need to use the heat of combustion of fuel and molar mass. First we will write the combustion reaction of gaseous benzene and acetylene gas. Then we will calculate the Hcomb0 from the thermodynamic value(Hf0) of compounds present in the reaction. By using the molar mass of the fuel, we will calculate the fuel value.

2) Formula:

i) Hcomb0 = m ×Hf, product0-n ×Hf, reactant0

ii) Fuel Value= Hcomb0molar mass ×number of moles of fuel

3) Given:

i) Benzene,   Hf0 = 82.9 kJ/mol    Chemistry: An Atoms-Focused Approach, Chapter 19, Problem 19.70QA , additional homework tip  1

ii) Benzene,   molar mass = 78.114 g/mol    Chemistry: An Atoms-Focused Approach, Chapter 19, Problem 19.70QA , additional homework tip  2

iii) Acethylene,   Hf0 =226.7 kJ/mol    Chemistry: An Atoms-Focused Approach, Chapter 19, Problem 19.70QA , additional homework tip  3

iv) Acethylene,   molar mass =26.038 g/mol

v) O2,   Hf0 = 0.0 kJ/mol    Chemistry: An Atoms-Focused Approach, Chapter 19, Problem 19.70QA , additional homework tip  4

vi) CO2 (g),   Hf0 = -393.5 kJ/mol    Chemistry: An Atoms-Focused Approach, Chapter 19, Problem 19.70QA , additional homework tip  5

vii) H2O (l),   Hf0 = -285.8 kJ/mol    Chemistry: An Atoms-Focused Approach, Chapter 19, Problem 19.70QA , additional homework tip  6

4) Calculations:

Write the balanced combustion reaction of benzene.

C6H6g+152O2g 6 CO2g+3 H2O l

Calculate the  Hcomb0 of benzene by using the thermodynamic value given from Appendix 4.

Hcomb0 = m ×Hf, product0-n ×Hf, reactant0

Hcomb0 = 6 × -393.5kJmol+3 × -285.8kJmol-1 × 82.9 kJmol+152 × 0.0kJmol

Hcomb0 =-3218.4 kJ-82.9 kJ= -3301.3 kJ

If we divide the absolute value of Hcomb0 by twice the molar mass of benzene, we will get the fuel value.

Fuel Value= Hcomb0molar mass ×number of moles of fuel

Fuel Value= 3301.3 kJ78.114 gmol ×1 mol= 42.26 kJ /g

The fuel value of benzene is 42.26 kJ/g.

Write the balanced combustion reaction of acetylene.

3 HCCH g+152O2g 6 CO2g+3 H2O l

Calculate the  Hcomb0 ofacetylene by using the thermodynamic value given from Appendix 4.

Hcomb0 = m ×Hf, product0-n ×Hf, reactant0

Hcomb0 = 6 × -393.5kJmol+3 × -285.8kJmol-3 × 226.7kJmol+152 × 0.0kJmol

Hcomb0 =-3218.4 kJ-680.1 kJ= -3898.5 kJ

If we divide the absolute value of Hcomb0 by the molar mass of acetylene, we will get the fuel value.

Fuel Value= Hcomb0molar mass ×number of moles of fuel

Fuel Value= 3898.5 kJ26.038 gmol ×3 mol= 49.91 kJ /g

The fuel value of acetyleneis 49.91 kJ/g.

The fuel value of one mole of benzene is lower than 3 mole of acetylene.

Conclusion:

The fuel value is calculated from the thermodynamic data, combustion reaction, and molar mass.

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Chapter 19 Solutions

Chemistry: An Atoms-Focused Approach

Ch. 19 - Prob. 19.11VPCh. 19 - Prob. 19.12VPCh. 19 - Prob. 19.13QACh. 19 - Prob. 19.14QACh. 19 - Prob. 19.15QACh. 19 - Prob. 19.16QACh. 19 - Prob. 19.17QACh. 19 - Prob. 19.18QACh. 19 - Prob. 19.19QACh. 19 - Prob. 19.20QACh. 19 - Prob. 19.21QACh. 19 - Prob. 19.22QACh. 19 - Prob. 19.23QACh. 19 - Prob. 19.24QACh. 19 - Prob. 19.25QACh. 19 - Prob. 19.26QACh. 19 - Prob. 19.27QACh. 19 - Prob. 19.28QACh. 19 - Prob. 19.29QACh. 19 - Prob. 19.30QACh. 19 - Prob. 19.31QACh. 19 - Prob. 19.32QACh. 19 - Prob. 19.33QACh. 19 - Prob. 19.34QACh. 19 - Prob. 19.35QACh. 19 - Prob. 19.36QACh. 19 - Prob. 19.37QACh. 19 - Prob. 19.38QACh. 19 - Prob. 19.39QACh. 19 - Prob. 19.40QACh. 19 - Prob. 19.41QACh. 19 - Prob. 19.42QACh. 19 - Prob. 19.43QACh. 19 - Prob. 19.44QACh. 19 - Prob. 19.45QACh. 19 - Prob. 19.46QACh. 19 - Prob. 19.47QACh. 19 - Prob. 19.48QACh. 19 - Prob. 19.49QACh. 19 - Prob. 19.50QACh. 19 - Prob. 19.51QACh. 19 - Prob. 19.52QACh. 19 - Prob. 19.53QACh. 19 - Prob. 19.54QACh. 19 - Prob. 19.55QACh. 19 - Prob. 19.56QACh. 19 - Prob. 19.57QACh. 19 - Prob. 19.58QACh. 19 - Prob. 19.59QACh. 19 - Prob. 19.60QACh. 19 - Prob. 19.61QACh. 19 - Prob. 19.62QACh. 19 - Prob. 19.63QACh. 19 - Prob. 19.64QACh. 19 - Prob. 19.65QACh. 19 - Prob. 19.66QACh. 19 - Prob. 19.67QACh. 19 - Prob. 19.68QACh. 19 - Prob. 19.69QACh. 19 - Prob. 19.70QACh. 19 - Prob. 19.71QACh. 19 - Prob. 19.72QACh. 19 - Prob. 19.73QACh. 19 - Prob. 19.74QACh. 19 - Prob. 19.75QACh. 19 - Prob. 19.76QACh. 19 - Prob. 19.77QACh. 19 - Prob. 19.78QACh. 19 - Prob. 19.79QACh. 19 - Prob. 19.80QACh. 19 - Prob. 19.81QACh. 19 - Prob. 19.82QACh. 19 - Prob. 19.83QACh. 19 - Prob. 19.84QACh. 19 - Prob. 19.85QACh. 19 - Prob. 19.86QACh. 19 - Prob. 19.87QACh. 19 - Prob. 19.88QACh. 19 - Prob. 19.89QACh. 19 - Prob. 19.90QACh. 19 - Prob. 19.91QACh. 19 - Prob. 19.92QACh. 19 - Prob. 19.93QACh. 19 - Prob. 19.94QACh. 19 - Prob. 19.95QACh. 19 - Prob. 19.96QACh. 19 - Prob. 19.97QACh. 19 - Prob. 19.98QACh. 19 - Prob. 19.99QACh. 19 - Prob. 19.100QACh. 19 - Prob. 19.101QACh. 19 - Prob. 19.102QACh. 19 - Prob. 19.103QACh. 19 - Prob. 19.104QACh. 19 - Prob. 19.105QACh. 19 - Prob. 19.106QACh. 19 - Prob. 19.107QACh. 19 - Prob. 19.108QACh. 19 - Prob. 19.109QACh. 19 - Prob. 19.110QACh. 19 - Prob. 19.111QACh. 19 - Prob. 19.112QACh. 19 - Prob. 19.113QACh. 19 - Prob. 19.114QACh. 19 - Prob. 19.115QACh. 19 - Prob. 19.116QACh. 19 - Prob. 19.117QACh. 19 - Prob. 19.118QACh. 19 - Prob. 19.119QACh. 19 - Prob. 19.120QACh. 19 - Prob. 19.121QACh. 19 - Prob. 19.122QACh. 19 - Prob. 19.123QACh. 19 - Prob. 19.124QACh. 19 - Prob. 19.125QACh. 19 - Prob. 19.126QACh. 19 - Prob. 19.127QACh. 19 - Prob. 19.128QACh. 19 - Prob. 19.129QACh. 19 - Prob. 19.130QACh. 19 - Prob. 19.131QACh. 19 - Prob. 19.132QACh. 19 - Prob. 19.133QACh. 19 - Prob. 19.134QACh. 19 - Prob. 19.135QACh. 19 - Prob. 19.136QACh. 19 - Prob. 19.137QACh. 19 - Prob. 19.138QACh. 19 - Prob. 19.139QACh. 19 - Prob. 19.140QACh. 19 - Prob. 19.141QACh. 19 - Prob. 19.142QA
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