Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
4th Edition
ISBN: 9780134787961
Author: Tony Gaddis, Godfrey Muganda
Publisher: PEARSON
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Expert Solution & Answer
Chapter 19, Problem 1FTE
Explanation of Solution
Purpose of the given code:
The given code is used to display the second element in a list “myList”. This list contains three elements.
Given code:
/* Set a reference "ref" to the first node in the list "myList" */
Node ref = myList; //Line 1
/* Increment the value of "ref" */
ref++;//Line 2
/* Display the element in the "ref" */
System.out.print(ref.value); //Line 3
Error in the given code:
- The error is present in “line 2” of given code. If user needs move on to the next node, then they should set a reference to the successor of the existing node. That is assign “ref” to “ref.next”.
- Therefore, user should replace “ref = ref.next” in the place of “ref++”...
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Students have asked these similar questions
What does the following function do for a given Linked List?
void fun1(struct node* head){if(head == NULL)return;fun1(head->next);printf("%d ", head->data);}
Apart from the main list in the list above, elements with the same value are also linked. According to this;
a) Write the Generic Node class.
b) Write the method that adds a new element to the end of the list.
JAVA CODE
Linked list. Complete the function that takes as a parameter the head of a linked list and prints the linked list in reverse order. If the linked list had the contents: of,the,and,on,a,an,ok. Then the correct output would be: ok,an,a,on,and,the,of.
Given:
struct node { char word[31];
struct node *prev, next;
};
void print_reverse(struct node *head) {
}
Chapter 19 Solutions
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Ch. 19.1 - Prob. 19.1CPCh. 19.1 - Prob. 19.2CPCh. 19.3 - Prob. 19.4CPCh. 19 - A list is a collection that _____. a. associates...Ch. 19 - Prob. 2MCCh. 19 - Prob. 3MCCh. 19 - Prob. 4MCCh. 19 - Prob. 5MCCh. 19 - Prob. 6MCCh. 19 - Prob. 7MC
Ch. 19 - Prob. 11TFCh. 19 - Prob. 12TFCh. 19 - Prob. 13TFCh. 19 - Prob. 14TFCh. 19 - Prob. 15TFCh. 19 - Prob. 16TFCh. 19 - Prob. 17TFCh. 19 - Prob. 18TFCh. 19 - Prob. 19TFCh. 19 - Prob. 20TFCh. 19 - Prob. 1FTECh. 19 - Prob. 2FTECh. 19 - Prob. 3FTECh. 19 - Prob. 4FTECh. 19 - Prob. 5FTECh. 19 - Prob. 1AWCh. 19 - Prob. 2AWCh. 19 - Prob. 3AWCh. 19 - Prob. 4AWCh. 19 - Prob. 3SACh. 19 - Prob. 4SACh. 19 - Prob. 5SACh. 19 - Consult the online Java documentation and...Ch. 19 - Prob. 1PCCh. 19 - Prob. 2PC
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- When removing a node from a linked list, what are the two steps?arrow_forward*** don't use hand writing ***** write the number of answer***** Java Program **** Write a Program for Circular Linked List for this operations. To insert a node at head locationarrow_forwardOcaml Mode Write a function mode : ’a list -> ’a = that given a (nonempty) list it returns an element that repeats the most times (if ties exist, return the element among them that appears first in the list). examples mode [1;2;1;4;2;5;1;2;6];; - : int = 1 mode [’a’;’b’;’c’;’b’;’a’;’b’;’d’;’c’;’d’];; - : char = ’b’arrow_forward
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- Part2: LinkedList implementation 1. Create a linked list of type String Not Object and name it as StudentName. 2. Add the following values to linked list above Jack Omar Jason. 3. Use addFirst to add the student Mary. 4. Use addLast to add the student Emily. 5. Print linked list using System.out.println(). 6. Print the size of the linked list. 7. Use removeLast. 8. Print the linked list using for loop for (String anobject: StudentName){…..} 9. Print the linked list using Iterator class. 10. Does linked list hava capacity function? 11. Create another linked list of type String Not Object and name it as TransferStudent. 12. Add the following values to TransferStudent linked list Sara Walter. 13. Add the content of linked list TransferStudent to the end of the linked list StudentName 14. Print StudentName. 15. Print TransferStudent. 16. What is the shortcoming of using Linked List?arrow_forwardint F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodesarrow_forwardWhat does this part of code do? void addRecord(Node *& head, Node *& tail, string name, double balance){ Node *newNode = new Node; newNode->name = name; newNode->balance = balance; newNode->next = NULL; newNode->prev = NULL; // If list is empty, make newNode the first node if(head == NULL){ head = newNode; tail = newNode; } else{ Node *temp = head; // Loop through list until temp->next is NULL while(temp->next != NULL){ temp = temp->next; } temp->next = newNode; newNode->prev = temp; tail = newNode; }} /*arrow_forward
- Apart from the main list in the list above, elements with the same value are also linked. According to this; a) Write the Generic Node class. b) Write the method that adds a new element to the end of the list.arrow_forwardCode --- linked list, swap every two adjacent nodesand return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space.You may not modify the values in the list,only nodes itself can be changed."""class Node(object): def __init__(self, x): self.val = x.arrow_forwardGiven the class Node below. We have a linked list with head node “A”. Write the code to remove the node “C” in the following linked list. public class Node { public String element; public Node next; }arrow_forward
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