Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 2, Problem 2.16P
For a normally consolidated soil, the following is given:
Determine the following:
- a. The compression index, Cc.
- b. The void ratio corresponding to pressure of 200 kN/m2
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PROBLEM 50: Compute the compression index of undisturbed clay having a plastic limit of 32% and a plasticity index of 8%
The compression diagram for a precompressed clay indicates that it had been compressed under a pressure of 240 kN/m2. The compression index is 0.9; its void ratio under a pressure of 180 kN/m2 is 1.5. Estimate the void ratio if the pressure is increased to 360 kN/m2.
a.
0.70
b.
1.246
c.
1.46
d.
1.34
Chapter 2 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
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- What is the active pressure coefficient for a soil with 28˚ angle of internal friction and cohesion of 20 kPa? What will be the effect if the cohesion is decreased to 5 kPa?arrow_forwardquestion 5 A rectangular footing (4.67 x 4.45 m.) is placed 1.62 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.22 meters and followed by clay for the next 5.85 meters. The force acting on the footing is 10,929 kN. Determine the settlement of the consolidating layer in mm. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.6 kN/m3. Clay has the following properties: Unit weight = 18.6 kN/m3, Void ratio = 28, Liquid limit = 43. Round off to two decimal places.arrow_forwardA rectangular footing (4.55 x 4.8 m.) is placed 1.42 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 5.55 meters and followed by clay for the next 5.98 meters. The force acting on the footing is 10,647 kN. Determine the settlement of the consolidating layer in mm. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.7 kN/m3. Clay has the following properties: unit weight = 18.9 kN/m^3, void ratio=30, liquid limit = 43arrow_forward
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- Calculate the internal friction angle of a f-type soil that fails at shear stress of 150 kN/m2 when tested under a normal stress of 240 kN/m2.arrow_forwardFor a given consolidated clay: Gs= 2.71; LL= 45; In situ average effective overburden pressure = 120 kPa; In situ void ratio= 0.80 ; Thickness of clay layer = 4m ; average increase of effective stress on clay layer= 40 kPa; Effective pressure at the mid-height of clay layer= 60 kPa; Swell Index (Cs)= 1/5 Cc. Compute the pre-consolidation pressure in kPa. Show free body diagram a.92.9 b.100.5 c.49 d.87.64arrow_forwardThe top 500 m of a site consists of a clayey sand with void ratio of 0.90 and water content of 20.0%. The specific gravity of the soil grains is 2.68. When the ground is compacted at the same water content, there is 45 mm reduction in the thickness of this layer. Determine the new void ratio and the unit weight of the soil. Show handwritten solutionsarrow_forward
- Estimate the vertical coefficient of permeability for a uniform clay deposit where representative test results are as shown: LL = 92, PL = 34 percent of clay size particles in the soil =40 void ratio ( approximate ) = 1.75arrow_forwardFor a normally consolidated clay, the following were recorded; confining pressure= σ3 = 140KPa and ∆σd = 264 KPa. Find ∅.arrow_forward
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