Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 2, Problem 2.9P
To determine
Calculate the magnitude of k of the clay.
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A normally consolidated clay has the following values void ratio e = 1.2, k(cm/sec) = 0.2 x 10^-6
And void ratio e = 1.9, 0.91x10^-6. Estimate the magnitude k of the clay at a void ratio (e) of 0.9. Use k = C (e^n)/1+e.
The results of a consolidated drained triaxial shear test on a normally consolidated clay are shown in the figure. The angle of internal friction is:--
Experimental data for clay specimen obtained initial values of e1 = 1.12 and P1 = 90 kPa, and final values of e2 = 0.90 and P2 = 460 kPa
Solve for the compression index
Chapter 2 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
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- Consolidation of an undrained clay occurs at an effective pressure of 100 kPa and a shear stress of 40 kPa. The ratio of effective pressure to shear stress in drained clay is 2 to 1. If the shear stress at zero effective pressure, To, is 10 kPa, what is the pore water pressure at failure? A. 10 kPa в. 40 кра с. 53 кра D. 67 kPaarrow_forwardData from an oedometer test using a clay specimen are plotted in the graph shown below. If the compression index is equal to 0.6, calculate the void ratio (e2) missing at Point C, which is associated with a vertical effective stress equal to 105 kPaarrow_forwardA consolidated-drained triaxial test on a sand yields the results:All-around confining pressure = σ3 = 30 lb/in2Added axial stress at failure = Δσ = 96 lb/in2Determine the shear stress parameters (i.e., Φ' and c')arrow_forward
- A consolidated-drained triaxial test was conducted on a normally consolidated clay.The results were as follows:σ3 = 276 kN/m2(Δσd)f = 276 kN/m2a. Find the angle of friction. ϕ'.b. What is the angle that the failure plane makes with the major principal stress?c. C. Determine the normal stress σ' and the shear stress τf on the failure plane.arrow_forwardFor a normally consolidated soil, the following is given: Determine the following: a. The compression index, Cc. b. The void ratio corresponding to pressure of 200 kN/m2arrow_forwardFor a normally consolidated clay, these are the results of a drained triaxial test: confining pressure = 112 kPa deviator stress at failure = 175 kPaa) Find the angle of internal friction, ø’.b) Determine the angle θ that the failure plane makes with the major principal plane.c) Find the normal stress σ’ and the shear stress τf on the failure plane.d) Determine the effective normal stress on the plane of maximum shear stress.arrow_forward
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