Chapter 2, Problem 2.60QP

(a)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

• The prefixes on each atom indicates the number of that atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’.  This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar.  Binary acids are named based on the non-metal atom present in them.  Oxoacids are named on the basis of polyatomic anion present in them.

Answer to Problem 2.60QP

The given compound $KClO$ is named as Potassium hypochlorite.

Explanation of Solution

$KClO$ has potassium K, chromium Cr and oxygen O atoms.  Cation of the compound is $K^{+}$ and anion of the compound is $Cl{O}^{-}$ and their names are potassium ion and chlorate ion respectively.  Hence the compound is named as sodium chlorate.

(b)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $A{g}_{2}C{O}_3$ is named as Silver carbonate

Explanation of Solution

$A{g}_{2}C{O}_3$ has cation $A{g}^{+}$ and anion $C{O}_3^{2-}$.  Their names are silver ion and carbonate ion.  Hence the compound is named as silver carbonate.

(c)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $FeC{l}_2$ is named as Iron(II) chloride.

Explanation of Solution

The cation and anion in $FeC{l}_2$ are $F{e}^{2+}$ and $C{l}^{-}$ respectively.  Their names are iron(II) ion and chloride ion respectively.

The compound is named as iron(II) chloride.

(d)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $KMn{O}_4$ is named as Potassium permanganate.

Explanation of Solution

The cation and anion in $KMn{O}_4$ are $K^{+}$ and $Mn{O}_4^{-}$ respectively.  Their names are potassium ion and permanganate ion respectively.

The compound is named as potassium permanganate.

(e)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $CsCl{O}_3$ is named as Cesium chlorate.

Explanation of Solution

The cation and anion in $CsCl{O}_3$ are $C{s}^{+}$ and $Cl{O}_3^{-}$ respectively.  Their names are cesium ion and chlorate ion respectively.

The compound is named as cesium chlorate.

(f)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $HIO$ is named as Hypoiodous acid.

Explanation of Solution

Oxoacids are named on the basis of polyatomic anion present in them.  The polyatomic anion in $HIO$ is $I{O}^{-}$ and its name is hypoiodous.  Name of the compound is hypoiodous acid.

(g)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $FeO$ is named as Iron(II) oxide.

Explanation of Solution

The cation and anion in $FeO$ are $F{e}^{2+}$ and $O_2^{-}$ respectively.  Their names are iron(II) ion and oxide ion respectively.

The compound is named as Iron(II) oxide.

(h)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $F{e}_2{O}_3$ is named as Iron(III) oxide.

Explanation of Solution

The cation and anion in $F{e}_2{O}_3$ are $F{e}^{3+}$ and $O_2^{-}$ respectively.  Their names are iron(III) ion and oxide ion respectively.

Hence, the compound is named as Iron(III) oxide.

(i)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $TiC{l}_4$ is named as Titanium(IV) chloride.

Explanation of Solution

The cation and anion in $TiC{l}_4$ are $T{i}^{4+}$ and $C{l}^{-}$ respectively.  Their names are titanium(IV) ion and chloride ion respectively.

The compound is named as Titanium(IV) chloride.

(j)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $NaH$ is named as Sodium hydride.

Explanation of Solution

The cation and anion in $NaH$ are $N{a}^{+}$ and $H^{-}$ respectively.  Their names are sodium ion and hydride ion respectively.

The compound is named as sodium hydride.

(k)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $L{i}_{3}N$ is named as Lithium nitride.

Explanation of Solution

The cation and anion in $L{i}_{3}N$ are $L{i}^{+}$ and $N^{3-}$ respectively.  Their names are lithium ion and nitride ion respectively.

The compound is named asLithium nitride.

(l)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $N{a}_{2}O$ is named as Sodium oxide.

Explanation of Solution

The cation and anion in $N{a}_{2}O$ are $N{a}^{+}$ and $O^{2-}$ respectively.  Their names are sodium ion and oxide ion respectively.

The compound is named asSodium oxide.

(m)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $N{a}_2{O}_2$ is named as Sodium peroxide.

Explanation of Solution

The cation and anion in $N{a}_2{O}_2$ are $N{a}^{+}$ and $O_2^2{}^{-}$ respectively.  Their names are sodium ion and peroxide ion respectively.

The compound is named asSodium peroxide.

(n)

Interpretation Introduction

Interpretation:

The given compound has to be named.

Concept Introduction:

Refer part (a).

Answer to Problem 2.60QP

The given compound $FeC{l}_3.6H_{2}O$ is named as Iron(III) chloride hexahydrate.

Explanation of Solution

The compound $FeC{l}_3.6H_{2}O$ has cation $F{e}^{3+}$ and anion $C{l}^{-}$.  With reference to table 2.3 in text book, the names of the ions are iron(III) ion and chloride ion respectively.  6 water molecules are bonded to the molecule.  Hence name of the compound is Iron(III) chloride hexahydrate.