Explanation Given: ( e 1.3 ) 2 e − 0.3 e 1.3 + e − 1.4 Concept Used: Some of basic properties of exponential functions is b x b y = b x + y b x b y = b x − y Power rule: ( b x ) y = b x y Calculation: In order to evaluate the expression ( e 1.3 ) 2 e − 0.3 e 1.3 + e − 1.4 We will use basic properties of exponential functions, as ( e 1.3 ) 2 e − 0.3 e 1.3 + e − 1.4 = e 2.6 e − 0.3 e 1

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 2, Problem 4SP

To determine

To evaluate the problem

( e 1.3 )2e−0.3e1.3+e −1.4 .

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Chapter 2, Problem 3SP

Chapter 2, Problem 5SP

Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

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To evaluate the problem ( e 1.3 ) 2 e − 0.3 e 1.3 + e − 1.4 .

Solution Summary: The author explains how to evaluate the expression (e1.3).

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To evaluate the problem

( e 1.3 )2e−0.3e1.3+e −1.4 .

Want to see the full answer?

Chapter 2 Solutions

To evaluate the problem ( e 1.3 ) 2 e − 0.3 e 1.3 + e − 1.4 .

Solution Summary: The author explains how to evaluate the expression (e1.3).

Videos

To evaluate the problem ( e 1.3 )2e−0.3e1.3+e −1.4 .

Want to see the full answer?

Chapter 2 Solutions

To evaluate the problem

( e 1.3 )2e−0.3e1.3+e −1.4 .