Explanation Given Information: It is provided log 2 x + log 5 ( 2 x + 1 ) = ln x Formula Used: Identity: log b a = ln a ln b Calculation : Since it is provided that log 2 x + log 5 ( 2 x + 1 ) = ln x Use the above identity log b a = ln a ln b The above equation transforms to : ln x ln 2 + ln ( 2 x + 1 ) ln 5 = ln x ⇒ ln ( 2 x + 1 ) ln 5 = ln x − ln x ln 2 ⇒ ln ( 2 x + 1 ) ln 5 = ln x ( 1 − 1 ln 2 ) ⇒ ln 2 ln ( 2 x + 1 ) = ln

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Question

Chapter 2.4, Problem 37PS

To determine

To Solve: log2x+log5(2x+1)=lnx to the nearest tenth.

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Chapter 2.4, Problem 36PS

Chapter 2.4, Problem 38PS

Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

Ch. 2.1 - Prob. 11PS Ch. 2.1 - Prob. 12PS Ch. 2.1 - Prob. 13PS Ch. 2.1 - Prob. 14PS Ch. 2.1 - Prob. 15PS Ch. 2.1 - Prob. 16PS Ch. 2.1 - Prob. 17PS Ch. 2.1 - Prob. 18PS Ch. 2.1 - Prob. 19PS Ch. 2.1 - Prob. 20PS Ch. 2.1 - Prob. 21PS Ch. 2.1 - Prob. 22PS Ch. 2.1 - Prob. 23PS Ch. 2.1 - Prob. 24PS Ch. 2.1 - Prob. 25PS Ch. 2.1 - Prob. 26PS Ch. 2.1 - Prob. 27PS Ch. 2.1 - Prob. 28PS Ch. 2.1 - Prob. 29PS Ch. 2.1 - Prob. 30PS Ch. 2.1 - Prob. 31PS Ch. 2.1 - Prob. 32PS Ch. 2.1 - Prob. 33PS Ch. 2.1 - Prob. 34PS Ch. 2.1 - Prob. 35PS Ch. 2.1 - Prob. 36PS Ch. 2.1 - Prob. 37PS Ch. 2.1 - Prob. 38PS Ch. 2.1 - Prob. 39PS Ch. 2.1 - Prob. 40PS Ch. 2.1 - Prob. 41PS Ch. 2.1 - Prob. 42PS Ch. 2.1 - Prob. 43PS Ch. 2.1 - Prob. 44PS Ch. 2.1 - Prob. 45PS Ch. 2.1 - Prob. 46PS Ch. 2.1 - Prob. 47PS Ch. 2.1 - Prob. 48PS Ch. 2.1 - Prob. 49PS Ch. 2.1 - Prob. 50PS Ch. 2.1 - Prob. 51PS Ch. 2.1 - Prob. 52PS Ch. 2.1 - Prob. 53PS Ch. 2.1 - Prob. 54PS Ch. 2.1 - Prob. 55PS Ch. 2.1 - Prob. 56PS Ch. 2.1 - Prob. 57PS Ch. 2.1 - Prob. 58PS Ch. 2.1 - 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Prob. 48PS Ch. 2.2 - Prob. 49PS Ch. 2.2 - Prob. 50PS Ch. 2.2 - Prob. 51PS Ch. 2.2 - Prob. 52PS Ch. 2.2 - Prob. 53PS Ch. 2.2 - Prob. 54PS Ch. 2.2 - Prob. 55PS Ch. 2.2 - Prob. 56PS Ch. 2.2 - Prob. 57PS Ch. 2.2 - Prob. 58PS Ch. 2.2 - Prob. 59PS Ch. 2.2 - Prob. 60PS Ch. 2.3 - Prob. 1PS Ch. 2.3 - Prob. 2PS Ch. 2.3 - Prob. 3PS Ch. 2.3 - Prob. 4PS Ch. 2.3 - Prob. 5PS Ch. 2.3 - Prob. 6PS Ch. 2.3 - Prob. 7PS Ch. 2.3 - Prob. 8PS Ch. 2.3 - Prob. 9PS Ch. 2.3 - Prob. 10PS Ch. 2.3 - Prob. 11PS Ch. 2.3 - Prob. 12PS Ch. 2.3 - Prob. 13PS Ch. 2.3 - Prob. 14PS Ch. 2.3 - Prob. 15PS Ch. 2.3 - Prob. 16PS Ch. 2.3 - Prob. 17PS Ch. 2.3 - Prob. 18PS Ch. 2.3 - Prob. 19PS Ch. 2.3 - Prob. 20PS Ch. 2.3 - Prob. 21PS Ch. 2.3 - Prob. 22PS Ch. 2.3 - Prob. 23PS Ch. 2.3 - Prob. 24PS Ch. 2.3 - Prob. 25PS Ch. 2.3 - Prob. 26PS Ch. 2.3 - Prob. 27PS Ch. 2.3 - Prob. 28PS Ch. 2.3 - Prob. 29PS Ch. 2.3 - Prob. 30PS Ch. 2.3 - Prob. 31PS Ch. 2.3 - Prob. 32PS Ch. 2.3 - Prob. 33PS Ch. 2.3 - Prob. 34PS Ch. 2.3 - Prob. 35PS Ch. 2.3 - Prob. 36PS Ch. 2.3 - 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Prob. 17PE Ch. 2 - Prob. 18PE Ch. 2 - Prob. 19PE Ch. 2 - Prob. 20PE Ch. 2 - Prob. 21PE Ch. 2 - Prob. 22PE Ch. 2 - Prob. 23PE Ch. 2 - Prob. 24PE Ch. 2 - Prob. 25PE Ch. 2 - Prob. 26PE Ch. 2 - Prob. 27PE Ch. 2 - Prob. 28PE Ch. 2 - Prob. 29PE Ch. 2 - Prob. 30PE Ch. 2 - Prob. 1SP Ch. 2 - Prob. 2SP Ch. 2 - Prob. 3SP Ch. 2 - Prob. 4SP Ch. 2 - Prob. 5SP Ch. 2 - Prob. 6SP Ch. 2 - Prob. 7SP Ch. 2 - Prob. 8SP Ch. 2 - Prob. 9SP Ch. 2 - Prob. 10SP Ch. 2 - Prob. 11SP Ch. 2 - Prob. 12SP Ch. 2 - Prob. 13SP Ch. 2 - Prob. 14SP Ch. 2 - Prob. 15SP Ch. 2 - Prob. 16SP Ch. 2 - Prob. 17SP Ch. 2 - Prob. 18SP Ch. 2 - Prob. 19SP Ch. 2 - Prob. 20SP Ch. 2 - Prob. 21SP Ch. 2 - Prob. 22SP Ch. 2 - Prob. 23SP Ch. 2 - Prob. 24SP Ch. 2 - Prob. 25SP Ch. 2 - Prob. 26SP Ch. 2 - Prob. 27SP Ch. 2 - Prob. 28SP Ch. 2 - Prob. 29SP Ch. 2 - Prob. 30SP Ch. 2 - Prob. 31SP Ch. 2 - Prob. 32SP Ch. 2 - Prob. 33SP Ch. 2 - Prob. 34SP Ch. 2 - Prob. 35SP Ch. 2 - Prob. 36SP Ch. 2 - Prob. 37SP Ch. 2 - Prob. 38SP Ch. 2 - Prob. 39SP Ch. 2 - Prob. 40SP Ch. 2 - Prob. 41SP Ch. 2 - Prob. 42SP Ch. 2 - Prob. 43SP Ch. 2 - Prob. 44SP Ch. 2 - Prob. 45SP Ch. 2 - Prob. 46SP Ch. 2 - Prob. 47SP Ch. 2 - Prob. 48SP Ch. 2 - Prob. 49SP Ch. 2 - Prob. 50SP Ch. 2 - Prob. 51SP Ch. 2 - Prob. 52SP Ch. 2 - Prob. 53SP Ch. 2 - Prob. 54SP Ch. 2 - Prob. 55SP Ch. 2 - Prob. 56SP Ch. 2 - Prob. 57SP Ch. 2 - Prob. 58SP Ch. 2 - Prob. 59SP Ch. 2 - Prob. 60SP Ch. 2 - Prob. 61SP Ch. 2 - Prob. 62SP Ch. 2 - Prob. 63SP Ch. 2 - Prob. 64SP Ch. 2 - Prob. 65SP Ch. 2 - Prob. 66SP Ch. 2 - Prob. 67SP Ch. 2 - Prob. 68SP Ch. 2 - Prob. 69SP Ch. 2 - Prob. 70SP Ch. 2 - Prob. 71SP Ch. 2 - Prob. 72SP Ch. 2 - Prob. 73SP Ch. 2 - Prob. 74SP Ch. 2 - Prob. 75SP Ch. 2 - Prob. 76SP Ch. 2 - Prob. 77SP Ch. 2 - Prob. 78SP Ch. 2 - Prob. 79SP Ch. 2 - Prob. 80SP Ch. 2 - Prob. 81SP Ch. 2 - Prob. 82SP Ch. 2 - Prob. 83SP Ch. 2 - Prob. 84SP Ch. 2 - Prob. 85SP Ch. 2 - Prob. 86SP Ch. 2 - Prob. 87SP Ch. 2 - Prob. 88SP Ch. 2 - Prob. 89SP Ch. 2 - Prob. 90SP Ch. 2 - Prob. 91SP Ch. 2 - Prob. 92SP Ch. 2 - Prob. 93SP Ch. 2 - 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log 2 x + log 5 ( 2 x + 1 ) = ln x to the nearest tenth.

Solution Summary: The author explains how the above equation transforms to: lmathrm

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To Solve: log2x+log5(2x+1)=lnx to the nearest tenth.

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Chapter 2 Solutions