Explanation Given information : f ( t ) = 3 − ( 5 + 2 t ) 3 Formula Used: ( a + b ) 3 = a 3 + 3 a 2 b + 3 a b 2 + b 3 Concept Involved: Domain of a function means the values of the input that gives a defined output to the function. Whenever we are finding the domain, we need to look out for two mail restrictions: Negative inside an even square root if we have a radical function Zero in the denominator if we have a rational function Note: Polynomials will not have any restrictions. Domain of polynomial will be all real numbers. Calculation: If we expand the given function, we will end up getting a cubic polynomial as follows: f ( t ) = 3 − ( 5 + 2 t ) 3 Applying the formula ( a + b ) 3 = a 3 + 3 a 2 b + 3 a b 2 + b 3 to expand ( 5 + 2 t ) 3 f ( t ) = 3 − ( 5 + 2 t ) 3 = 3 − ( 5 3 + 3 ( 5 ) 2 ( 2 t ) + 3 (<

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 2.3, Problem 8PS

To determine

Toidentify:all suspicious points and points of discontinuity.

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Chapter 2.3, Problem 7PS

Chapter 2.3, Problem 9PS

Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

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Toidentify :all suspicious points and points of discontinuity.

Solution Summary: The author explains that if we expand the given function, we will end up getting a cubic polynomial.

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Chapter 2 Solutions