The possible number of positive and negative real zeros of
Answer to Problem 57CR
Two or no positive zeros, one or no negative zero.
Explanation of Solution
Concept Used:
Descartes’s Rule of Signs:
Let
1. The number of positive real zeros of f is either equal to the number of variations in sign of
2. The number of negative real zeros of f is either equal to the number of variations in sign of
Consider the polynomial
It has 2 variations in signs, which implies that the polynomial has either 2 positive zeros or no positive zero.
Now consider,
It has 1 variation in signs, which implies that the polynomial has either 1 negative zeros or no negative zero.
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
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