Concept explainers
(a)
To apply: The leading coefficient test.
(a)
Explanation of Solution
Given information:
Graph:
By leading coefficient test:
As the x3is a leading variable and its coefficient is 1 which is a positive coefficient.
And x is having odd number as its degree.
So when the large cubes were taken than x3 will be dominating
For
For
The graph will be:
(b)
To find: The real zeroes of the polynomial.
(b)
Explanation of Solution
Given information:
Graph:
The roots of the equation
The curve will pass through -5, 0 and 5.
(c)
To draw: The sufficient solution points.
(c)
Explanation of Solution
Given information:
Graph:
Plotting points:
F(x) | x |
24 | -1 |
0 | 0 |
-24 | 1 |
So the curve also passes through (-1, 24), (0, 0), (1, -24)
(d)
To draw: A continuous curve for the points.
(d)
Explanation of Solution
Given information:
Graph:
Continuous curve through the points
Points are:(-5,0) (-1,26) (0,0) (1,-24) (5,0)
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning