Organic Chemistry
Organic Chemistry
3rd Edition
ISBN: 9781119338352
Author: Klein
Publisher: WILEY
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Chapter 2, Problem 65IP

(a)

Interpretation Introduction

Interpretation:

Molecular formula of Ramelteon has to be written.

Concept Introduction:

Molecular formula shows that the actual number of atoms of each element that are present in a molecule of the compound.

(b)

Interpretation Introduction

Interpretation:

Number of sp3 hybridized carbon atoms that are present in this given structure has to be determined.

Concept Introduction:

The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.

The steric number is the combination of both number of σ -bonds and number of lone pairs involved in a particular molecule.

If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.

If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.

If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.

(c)

Interpretation Introduction

Interpretation:

Number of sp2 hybridized carbon atoms that are present in this given structure has to be determined.

Concept Introduction:

The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.

The steric number is the combination of both number of σ -bonds and number of lone pairs involved in a particular molecule.

If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.

If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.

If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.

(d)

Interpretation Introduction

Interpretation:

Number of sp hybridized carbon atoms that are present in this given structure has to be determined.

Concept Introduction:

The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.

The steric number is the combination of both number of σ -bonds and number of lone pairs involved in a particular molecule.

If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.

If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.

If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.

(e)

Interpretation Introduction

Interpretation:

The lone pair of electrons present in the given structure has to be identified.

Concept introduction:

The unshared electrons of an atom that does not involve in bonding are called lone pair.

Steps to determine the lone of pair of electrons,

  • Appropriate valence electron has to be known.
  • The actual number of valence electrons exhibited by the atom has to be known.
  • Count the number of bonds and assign the number of lone pair.

A formal charge (FC) is the charge assigned to an atom in a molecule, irrespective of relative electronegativity by thinking that electrons in all chemical bonds are shared equally among atoms. Electrons can be tracked by formal charge.

(f)

Interpretation Introduction

Interpretation:

The lone pair of electrons is delocalized or not has to be identified.

Concept introduction:

The unshared electrons of an atom that does not involve in bonding are called lone pair.

Steps to determine the lone of pair of electrons,

  • Appropriate valence electron has to be known.
  • The actual number of valence electrons exhibited by the atom has to be known.
  • Count the number of bonds and assign the number of lone pair.

A formal charge (FC) is the charge assigned to an atom in a molecule, irrespective of relative electronegativity by thinking that electrons in all chemical bonds are shared equally among atoms. Electrons can be tracked by formal charge.

(g)

Interpretation Introduction

Interpretation:

Geometry of the atoms except hydrogen has to be identified.

Concept introduction:

The steric number is the combination of both number of σ -bonds and number of lone pairs involved in a particular molecule.

The geometry of the central atom will be determined by counting the steric number followed by the hybridization state of that central atom and finally electronic arrangement of atoms in space.

If the steric number is 4, the central atom is sp3 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.

If the steric number is 3, the central atom is sp2 hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.

If the steric number is 2, the central atom is sp hybridized and the electronic arrangement of atoms in space (i.e. geometry) will be linear.

sp3 hybridized =    tetrahedral.

    trigonal pyramidal(if one lone pair of electron is present).

    bent geometry (if two lone pair of electrons are present).

sp2 hybridized =    trigonal planar.

sp hybridized =    linear.

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Chapter 2 Solutions

Organic Chemistry

Ch. 2.5 - Prob. 4LTSCh. 2.5 - Prob. 8PTSCh. 2.5 - The rich and varied flavors of toasted bread,...Ch. 2.5 - Prob. 5LTSCh. 2.5 - Prob. 10PTSCh. 2.5 - Prob. 11ATSCh. 2.8 - Prob. 6LTSCh. 2.8 - Prob. 12PTSCh. 2.8 - Prob. 13PTSCh. 2.8 - Prob. 14ATSCh. 2.9 - Prob. 7LTSCh. 2.9 - Prob. 15PTSCh. 2.9 - Prob. 16PTSCh. 2.9 - The cation 1 has been shown to lose a proton (H+)...Ch. 2.10 - Prob. 18CCCh. 2.10 - Prob. 19CCCh. 2.10 - Prob. 20CCCh. 2.10 - Prob. 21CCCh. 2.10 - Prob. 22CCCh. 2.10 - Prob. 23CCCh. 2.10 - Prob. 24CCCh. 2.10 - Prob. 25CCCh. 2.11 - Prob. 8LTSCh. 2.11 - Prob. 26PTSCh. 2.11 - Prob. 27ATSCh. 2.11 - Prob. 28ATSCh. 2.12 - Prob. 9LTSCh. 2.12 - Prob. 29PTSCh. 2.12 - The dragmacidin class of natural products has been...Ch. 2.13 - Prob. 10LTSCh. 2.13 - Prob. 31PTSCh. 2.13 - Prob. 32ATSCh. 2.13 - Prob. 33ATSCh. 2 - Prob. 34PPCh. 2 - Prob. 35PPCh. 2 - Prob. 36PPCh. 2 - Prob. 37PPCh. 2 - Prob. 38PPCh. 2 - Prob. 39PPCh. 2 - Prob. 40PPCh. 2 - Prob. 41PPCh. 2 - Prob. 42PPCh. 2 - Prob. 43PPCh. 2 - Prob. 44PPCh. 2 - Amino acids are biological compounds with the...Ch. 2 - Prob. 46PPCh. 2 - Prob. 47PPCh. 2 - Prob. 48PPCh. 2 - Prob. 49PPCh. 2 - Prob. 50PPCh. 2 - Prob. 51PPCh. 2 - Prob. 52PPCh. 2 - Prob. 53PPCh. 2 - Prob. 54PPCh. 2 - Prob. 55PPCh. 2 - Prob. 56PPCh. 2 - Prob. 57PPCh. 2 - Prob. 58PPCh. 2 - Prob. 59PPCh. 2 - Prob. 60PPCh. 2 - Prob. 61PPCh. 2 - Prob. 62PPCh. 2 - Enamines, compounds with an amino group attached...Ch. 2 - Prob. 64IPCh. 2 - Ramelteon is a hypnotic agent used in the...Ch. 2 - Prob. 66IPCh. 2 - Prob. 67IPCh. 2 - Prob. 68IPCh. 2 - The natural products 3 and 4 have similar core...Ch. 2 - Prob. 70IPCh. 2 - Prob. 71IPCh. 2 - Prob. 72IPCh. 2 - Prob. 73IPCh. 2 - Prob. 74IPCh. 2 - Prob. 75IPCh. 2 - Coumarin and its derivatives exhibit a broad array...Ch. 2 - Prob. 77IPCh. 2 - Prob. 78IPCh. 2 - Prob. 79IPCh. 2 - Prob. 80IPCh. 2 - Prob. 81CPCh. 2 - Prob. 82CPCh. 2 - Prob. 83CPCh. 2 - Prob. 84CP
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