Concept explainers
Write the formula for each of the following compounds:
- a. ammonium hydrogen phosphate
- b. mercury (I) sulfide
- c. silicon dioxide
- d. sodium sulfite
- e. aluminum hydrogen sulfate
- f. nitrogen trichloride
- g. hydiobromic acid
- h. bromous acid
- i. perbromic acid
- j. potassium hydrogen sulfide
- k. calcium iodide
- l. cesium perchlorate
(a)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of ammonium hydrogen phosphate is
Explanation of Solution
To determine: The formula of ammonium hydrogen phosphate.
The oxidation state of ammonium
Hydrogen phosphate
So, the formula of the given compound is
The formula of ammonium hydrogen phosphate is
(b)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of mercury (I) sulfide is
Explanation of Solution
To determine: The formula of mercury (I) sulfide.
The oxidation state of mercury is
Sulfide is an anion having oxidation state
So, the formula of the given compound is
The formula of mercury(I) sulfide is
(c)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of silicon dioxide is
Explanation of Solution
To determine: The formula of silicon dioxide
The oxidation state of silicon is
Dioxide is an anion having oxidation state
So, the formula of the given compound is
The formula of silicon dioxide is
(d)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of sodium sulfite is
Explanation of Solution
To determine: The formula of sodium sulfite
The oxidation state of sodium is
Sulfite
So, the formula of the given compound is
The formula of sodium sulfite is
(e)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of alumunium hydrogen sulfate is
Explanation of Solution
To determine: The formula of alumunium hydrogen sulfate.
The oxidation state of alumunium is
Hydrogen sulfate
So, the formula of the given compound is
The formula of alumunium hydrogen sulfate is
(f)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of nitrogen trichloride is
Explanation of Solution
To determine: The formula of nitrogen trichloride.
The oxidation state of nitrogen is
The oxidation state of chlorine is
So, the formula of the given compound is
The formula of nitrogen trichloride is
(g)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of hydrobromic acid is
Explanation of Solution
To determine: The formula of of hydrobromic acid
The oxidation state of hydrogen
Bromine is an anion having oxidation state
So, the formula of the given compound is
The formula of hydrobromic acid is
(h)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of bromous acid is
Explanation of Solution
To determine: The formula of bromous acid
The oxidation state of hydrogen
Bromite
So, the formula of the given compound is
The formula of bromous acid is
(i)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of perbromic acid is
Explanation of Solution
To determine: The formula of perbromic acid
The oxidation state of hydrogen
Perbromate
So, the formula of the given compound is
The formula of perbromic acid is
(j)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of potassium hydrogen sulfide is
Explanation of Solution
To determine: The formula of potassium hydrogen sulfide
The oxidation state of potassium
Hydrogen sulfide is an anion having oxidation state
So, the formula of the given compound is
The formula of potassium hydrogen sulfide is
(k)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of calcium iodide is
Explanation of Solution
To determine: The formula of of calcium iodide
The oxidation state of calcium
Iodine is an anion having oxidation state
So, the formula of the given compound is
The formula of calcium iodide is
(l)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of cesium perchlorate is
Explanation of Solution
To determine: The formula of of cesium perchlorate.
The oxidation state of cesium
Perchlorate
So, the formula of the given compound is
The formula of cesium perchlorate is
Want to see more full solutions like this?
Chapter 2 Solutions
Study Guide for Zumdahl/Zumdahl/DeCoste’s Chemistry, 10th Edition
- For each of the following pairs of ions, write the formula of the compound they will form: K+,O2 NH4+,PO43 Al3+,O2 Na+,O32 Ba2+,PO43arrow_forwardClassify each compound as ionic or molecular: a.COb.ZnBr2c.CH4d.NaFarrow_forward32. Which of the following is a binary compound? A. hydrogen sulfate B. hydrogen sulfide C. ammonium sulfate D. calcium carbonate E. ammonium sulfidearrow_forward
- Write formulas for the following molecules: a. sodium bicarbonate b. chromium (III) nitrate c. lithium phosphate d. calcium sulfate e. iron (II) iodide f. potassium oxide g. phosphorus pentachloridearrow_forwardwrite the chemical formula for the following compounds g. magnesium phosphide h. potassium sulfide i. zinc hydroxide j.silver chromate k. iron(iii) oxide l. lead(ii) permanganatearrow_forwardWrite the correct chemical formula: a. Magnesium bromide b. Stannic nitrate c. Magnesium phosphate d. Ammonium sulphate e. calcium sulphate hemihydrate f. Cupric chloride dihydrate g. Aluminum carbide h. Nitrogen dioxide i. Strontium carbonate j. Barium hydrogen phosphatearrow_forward
- Solve explainarrow_forward1. Write the following compounds: a. Barium Selenide b. Magnesium phosphide c. Potassium nitride d. Aluminum fluoride e. Aluminum sulfidearrow_forwardA.Write the chemical formula for the ionic compounds. Please show your work. 1. Lithium acetate 2. Calcium bromide 3. Sodium hydride 4. Ammonium sulfate 5. Gallium Chloride 6. Ammonium oxide 7. Titanium (II) selenide 8. Lead (IV) sulfate 9. Manganese (VII) arsenide 10. Vanadium (V) nitride 11. Strontium B. Write the chemical formula for a covalent compound please show your work. 1. Antimony tribromide 2. Chlorine dioxide 3.Dihydrogen monoxide 4. Dinitrogen tetrahydride 5. Dichlorine heptoxide 6. lodine Pentafluoridearrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHER