Concept explainers
Write the formula for each of the following compounds:
- a. ammonium hydrogen phosphate
- b. mercury (I) sulfide
- c. silicon dioxide
- d. sodium sulfite
- e. aluminum hydrogen sulfate
- f. nitrogen trichloride
- g. hydiobromic acid
- h. bromous acid
- i. perbromic acid
- j. potassium hydrogen sulfide
- k. calcium iodide
- l. cesium perchlorate
(a)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of ammonium hydrogen phosphate is
Explanation of Solution
To determine: The formula of ammonium hydrogen phosphate.
The oxidation state of ammonium
Hydrogen phosphate
So, the formula of the given compound is
The formula of ammonium hydrogen phosphate is
(b)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of mercury (I) sulfide is
Explanation of Solution
To determine: The formula of mercury (I) sulfide.
The oxidation state of mercury is
Sulfide is an anion having oxidation state
So, the formula of the given compound is
The formula of mercury(I) sulfide is
(c)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of silicon dioxide is
Explanation of Solution
To determine: The formula of silicon dioxide
The oxidation state of silicon is
Dioxide is an anion having oxidation state
So, the formula of the given compound is
The formula of silicon dioxide is
(d)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of sodium sulfite is
Explanation of Solution
To determine: The formula of sodium sulfite
The oxidation state of sodium is
Sulfite
So, the formula of the given compound is
The formula of sodium sulfite is
(e)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of alumunium hydrogen sulfate is
Explanation of Solution
To determine: The formula of alumunium hydrogen sulfate.
The oxidation state of alumunium is
Hydrogen sulfate
So, the formula of the given compound is
The formula of alumunium hydrogen sulfate is
(f)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of nitrogen trichloride is
Explanation of Solution
To determine: The formula of nitrogen trichloride.
The oxidation state of nitrogen is
The oxidation state of chlorine is
So, the formula of the given compound is
The formula of nitrogen trichloride is
(g)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of hydrobromic acid is
Explanation of Solution
To determine: The formula of of hydrobromic acid
The oxidation state of hydrogen
Bromine is an anion having oxidation state
So, the formula of the given compound is
The formula of hydrobromic acid is
(h)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of bromous acid is
Explanation of Solution
To determine: The formula of bromous acid
The oxidation state of hydrogen
Bromite
So, the formula of the given compound is
The formula of bromous acid is
(i)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of perbromic acid is
Explanation of Solution
To determine: The formula of perbromic acid
The oxidation state of hydrogen
Perbromate
So, the formula of the given compound is
The formula of perbromic acid is
(j)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of potassium hydrogen sulfide is
Explanation of Solution
To determine: The formula of potassium hydrogen sulfide
The oxidation state of potassium
Hydrogen sulfide is an anion having oxidation state
So, the formula of the given compound is
The formula of potassium hydrogen sulfide is
(k)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of calcium iodide is
Explanation of Solution
To determine: The formula of of calcium iodide
The oxidation state of calcium
Iodine is an anion having oxidation state
So, the formula of the given compound is
The formula of calcium iodide is
(l)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 90E
The formula of cesium perchlorate is
Explanation of Solution
To determine: The formula of of cesium perchlorate.
The oxidation state of cesium
Perchlorate
So, the formula of the given compound is
The formula of cesium perchlorate is
Want to see more full solutions like this?
Chapter 2 Solutions
OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card for Zumdahl/Zumdahl/DeCoste's Chemistry, 10th Edition
- Give the total number of valence electrons in each of the following molecules. msp;a.N2Oc.C3H8b.B2H6d.NC13arrow_forwardFill in the blanks with the smallest integers possible. When gallium (Z=31) reacts with sulfur to form an ionic compound, each metal atom loses ______ electrons and each nonmetal gains_____electronss. There must be _____ gallium atoms for every _____sulfur atoms in the reaction.arrow_forwardDoes a cation gain protons to form a positive charge or does it lose electrons?arrow_forward
- If an atom of lithium (Li) bonded with an atom of fluorine (F), it would create a molecule of lithium fluoride (LiF). What could we say about this molecule? Group of answer choices A. It probably has an ionic bond B. The two atoms are sharing an electron C. It should have a charge D. It's probably nonpolar E. It probably has a covalent bondarrow_forwardSummarize the difference between ionic and molecular compounds?arrow_forwardThe dimeric hexamethyl dialuminum molecule Al2(CH3)6 has how many hydrogen atoms? A)3 b)6 c)18 d)36 The dimeric hexamethyl dialuminum molecule Al2(CH3)6 has how many total atoms? A)8 b) 24 c)26 d)52arrow_forward
- Refer to the nomenclature flowchart (Figure 3.11) to name each compound.a. XeO3 b. KClO c. CoSO4arrow_forwardThe following ionic compounds are found in common household products. Name each of the compounds:(a) Ca(H2PO4)2(b) FeSO4(c) CaCO3(d) MgO(e) NaNO2(f) KIarrow_forwardBarium reacts with a polyatomic ion to form a compound with the general formula Ba3(X)2. What would be the most likely formula for the compound formed between sodium and the polyatomic ion X? Select one: a. NaX b. Na3X2 c. Na2X2 d. Na3X e. Na2Xarrow_forward
- Have each member of your group select one of the molecules and complete steps a–d. Have members present their results to the rest of the group, explaining the reasoning they used to determine their answers. CS2 NCl3 CF4 CH2F2 a. Draw the Lewis structure.b. Determine the molecular geometry and draw it accurately.c. Indicate the polarity of any polar bonds within the structure.d. Classify the molecule as polar or nonpolar.arrow_forwardFormula of Calcium bicarbonate? ( including the positive ion and negative ion).arrow_forwardGive some examples of Ionized groups in Molecules?arrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax