GENETIC ANALYSIS: AN INTEG. APP. W/MAS
GENETIC ANALYSIS: AN INTEG. APP. W/MAS
2nd Edition
ISBN: 9781323142790
Author: Sanders
Publisher: Pearson Custom Publishing
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Chapter 20, Problem 14P

Given that maternal Bicoid activates the expression of hunchback (see Figure 18 .7 ), what would be the consequence of adding extra copies of the bicoid gene by transgenic means, thus creating a female fly with two (the wild-type condition), three, or four copies of the bicoid gene? How would hunchback expression be altered? What about the expression of other gap genes and pair-rule genes?

Chapter 20, Problem 14P, 18.14 Given that maternal Bicoid activates the expression of hunchback (see Figure ), what would be

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In Drosophila sex determination (Check all that apply.) A) XY individuals transcribe the Sxl gene early but not late. B XX individuals carry the Sxl gene, XY individuals do not. XX individuals transcribe the Sxl gene, XY individuals do not. XX individuals express the Sxl protein, XY individuals do not. E) The Sxl transcript (Pre-MRNA) is spliced differently in XX compared to XY individuals.
Why is it that mutations in bicoid and nanos exhibit genetic maternal effect in Drosophila (a mutation in the maternal parent produces a phenotype that shows up in the offspring), but mutations in runt and gooseberry do not?
Suppose a researcher has three different Drosophila strains that have mutations in the bicoid gene called bicoid-A, bicoid-B, and bicoid-C; the wild type is designated bicoid +. To study these mutations, phenotypically normal female flies that are homozygous for the given bicoid mutation were obtained, and their oocytes were analyzed using a Northern blot to determine the size and/or amount of the bicoid mRNA and in situ hybridization to determine the bicoid mRNA location within the oocyte. A wild-type strain was also analyzed as a control. In both cases, the probe was complementary to the bicoid mRNA and the results are shown below. (Anterior is on the left; posterior is on the right.) Northern blot 1 2 - 3 4 In situ hybridization Wild type Lane 1. Wild type (bicoid*) Lane 2. bicoid-A Lane 3. bicoid-B Lane 4. bicoid-C bicoid-B bicoid-A bicoid-C Which mutation is likely to cause the embryo to develop two "anterior" ends? bicoid-B Obicoid-A bicoid-C

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GENETIC ANALYSIS: AN INTEG. APP. W/MAS

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