Explanation Given: Sb – 132 Te – 139 Fr – 202 Ba – 123 The stability of nuclide depends upon the neutrons to proton ration. For elements, atomic number greater than 80 (Z > 82), the nuclide is stable if the N Z ratio is 1.5. If the ratio is more than 1.5, the preferred mode of decay is beta and if the ratio is less than 1.5, the preferred mode of decay is alpha decay and lighter elements undergo positron decay. a. Sb – 132 : Number of protons= 51 Number of neutrons= 132 – 51 = 81 N Z ratio = 81 51 = 1.58 Since the ratio is greater than 1.5, it will undergo beta decay. b...

2nd Edition

ISBN: 9780134449234

Author: Tro

Publisher: PEARSON

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Concept explainers

Writing and Balancing Nuclear Equations

A nuclear equation is a symbolic representation of a nuclear reaction using certain symbols. It is studied in nuclear chemistry and nuclear physics.

Question

Chapter 20, Problem 42E

Interpretation Introduction

To determine:

Predict a likely mode of decay for given unstable nuclides.

Expert Solution & Answer

Chapter 20 Solutions

Chemistry: Structure... -Masteringchem.

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