   Chapter 20, Problem 6PS

Chapter
Section
Textbook Problem

Suppose you find the CO concentration in your home is 10. ppm by volume at 1.00 atm pressure and 25 °C. What is the CO concentration in mg/L and in ppm by mass. (The average molar mass for dry air is 28.96 g/mol at 1.00 atm pressure and 25 °C.)

Interpretation Introduction

Interpretation:

The concentration of CO in mg/L and by mass should be determined.

Concept introduction:

• Parts per million (ppm): It is one of the important concentration expressing terms, and which describes grams of solute per million grams of total solutions.

ppm=MassofsoluteMassofsolution×1061ppm=1mg/L

• Mass of a substance from its number of moles is,

Number of moles×Molecularmass in grams=Massofsubstance

Explanation

Given,

Carbon monoxide concentration is 10ppm.

1ppm=1mg/L10ppm=10mg/L

Therefore the concentration of carbon monoxide in mg/L from the given value of ppm is,

10mg/L

10 ppm of CO in mg/L is 10mg/L

The given value of concentration of carbon monoxide in ppm can also expressed in mass as follows

The molar mass of dry air is 28.96g/mol.

10mg/L of CO means in 1 L there are 0.001molCO present

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