Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 20.2, Problem 2cTH
Box A and box B are now interchanged. It is observed that bulb 2 is now brighter than it was when box B was in that circuit.
- Is the resistance of box Agreater than, less than, or equal to the resistance of box B? Explain.
- Has the current through battery 1 changed? If so, how?
- Has the current through battery 2 changed? 1f so, how?
Expert Solution & Answer
Trending nowThis is a popular solution!
Learn your wayIncludes step-by-step video
schedule02:41
Students have asked these similar questions
Problem 3: (8% of Assignment Value)
A collection of four charges and four Gaussian surfaces are shown in the figure. The charges have values:
91 =
: +6.66 nC
92 = -6.66 nC
93 =
94 =
+19.2 nC
= -25.3 nC
The dashed lines represent the intersection of the closed three-dimensional surfaces with the plane of the image. If a charge is
shown within a dashed curve, then it is contained with the corresponding surface.
94
Otheexpertta.com
Part (a)
What is the electric flux, in newton squared meters per coulomb, through the first closed surface, S₁?
Part (b)
What is the electric flux, in newton squared meters per coulomb, through the second closed surface, S₂?
Part (c)
What is the electric flux, in newton squared meters per coulomb, through the third closed surface, S3?
Part (d)
What is the electric flux, in newton squared meters per coulomb, through the fourth closed surface, S4?
$4 =
N⚫m²/C
Grade Summary
Deductions
Potential
0%
100%
Problem 2: (8% of Assignment Value)
Two charges are placed on the
x axis with the positive direction towards the right of the page. As shown in the drawing, charge
92 is placed a distance
D (upper case) to the right of charge
91. Consider point
P which is located between the two charges and a distance
d (lower case) to the right of charge
91.
Let
91=-55
мс,
92 = +25
MC,
D=120
cm and
d=25
cm.
D.
91
P
92
Part (a)
If the electric field at point P is expressed as Ĕ = Ex ₁, what is the value of Ex, in newtons per coulomb?
Part (b)
Suppose a charge 93 = 20.0 μC is placed at point P. If the force on charge q3 is expressed as F = Fx ₁, what is the value of Fx, in newtons?
Fx = ||
N
G
D
Problem 12: (8% of Assignment Value)
An electron moving at 3.85 × 103 m/s in a 1.3 T magnetic field experiences a magnetic force of 1.55 × 10-16 N.
What angle (in degrees, between 0 and 90°) does the velocity of the electron make with the magnetic field?
0 = ||
sin()
cos()
tan()
cotan()
asin()
acos()
atan() acotan()
sinh()
cosh() tanh() cotanh()
Degrees Radians
78 9
HOME
4 5
* 1 2
+
-
0
BACKSPACE
Submit
Hint
Feedback
I give up!
Submission(s) Remaining
3
->
END
DEL
CLEAR
Chapter 20 Solutions
Tutorials in Introductory Physics
Ch. 20.1 - In tutorial, you compared the relative brightness...Ch. 20.1 - Use the model for electric current to rank the...Ch. 20.1 - Rang the brightness of the bulbs. Explain your...Ch. 20.1 - A wire is now added to the circuit as shown. i....Ch. 20.1 - Rank the networks according to their equivalent...Ch. 20.1 - How does adding a single bulb to a circuit in...Ch. 20.1 - How does adding a single bulb to a circuit in...Ch. 20.1 - The network AE above are connected, in turn, to...Ch. 20.1 - Rank the bulbs in order from brightest to dimmest....Ch. 20.1 - Suppose that a switch has been added to the...
Ch. 20.2 - The circuit at right consists of a bulb in series...Ch. 20.2 - The circuit at right consists of a bulb in series...Ch. 20.2 - The circuit at right consists of a bulb in series...Ch. 20.2 - In the circuit at right, the voltage across bulb 1...Ch. 20.2 - Prob. 2bTHCh. 20.2 - Box A and box B are now interchanged. It is...Ch. 20.2 - Consider the circuit as shown. i. Rank bulbs A, B,...Ch. 20.2 - b. A student cuts the write between bulbs A and C...Ch. 20.2 - Consider the following discussion between two...Ch. 20.2 - Rank bulbs 16 in order or brightness. Explain your...Ch. 20.2 - Rank the voltages across the bulbs. Explain your...Ch. 20.2 - Write an equation that relates the voltage across...Ch. 20.2 - Bulb 1 is removed from its socket. i. Does the...Ch. 20.3 - Describe the behavior of the bulb in the two...Ch. 20.3 - A second identical bulb is flow added to the...Ch. 20.3 - Just after the switch is closed: • what is the...Ch. 20.3 - A long time after the switch is closed: • rank the...Ch. 20.3 - Summarize your results by describing the behavior...
Additional Science Textbook Solutions
Find more solutions based on key concepts
Write electron configurations for each element. Use the symbol of the previous noble gas in brackets to represe...
Introductory Chemistry (6th Edition)
Why is it necessary to be in a pressurized cabin when flying at 30,000 feet?
Anatomy & Physiology (6th Edition)
11. A 1.0-cm-thick layer of water stands on a horizontal slab of glass. A light ray in the air is incident on t...
College Physics: A Strategic Approach (3rd Edition)
3. In a test of his chromosome theory of heredity, Morgan crossed an F1 female Drosophila with red eyes to a m...
Genetic Analysis: An Integrated Approach (3rd Edition)
Choose the best answer to each of the following. Explain your reasoning. The fact that we always see the same f...
Cosmic Perspective Fundamentals
Using the South Atlantic as an example, label the beginning of the normal polarity period C that began 2 millio...
Applications and Investigations in Earth Science (9th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Problem 9: (8% of Assignment Value) Consider the circuit shown, where R₁ = 10 kQ, R₂ = 18 kQ, R3 = = 7.5 kg, R4 = 10 k, and R5 : = 12.5 ΚΩ. The battery voltages are Vi = 12.0 V and V2 = 24.0 V. www + ww R₁ R₂ www R5 R3 4|| www RA Part (a) What is the potential difference in volts across resistor R3 ? Part (b) What is the potential difference in volts across resistor R5? Part (c) What is the power dissipated in milliwatts in resistor R5 ? Part (d) What is the power delivered to the circuit by the 24 V battery in milliwatts? P = || mW Grade Summary Deductionsarrow_forwardProblem 4: (8% of Assignment Value) = Charge 91 where a = = 0.75 m. The point P has coordinates (a, b), where b = 0.35 m. A third charge 93 = 19 nC will be placed later. :8 nC is located at the coordinate system origin, while charge 92 = 5.05 nC is located at (a, 0), Ул P (a,b) Part (a) Find the electric potential Vp at point P, in volts. Assume the potential is zero at infinity. Part (b) How much work W, in joules, would you have to do to bring the third charge, 93, from very far away to the point P? Part (c) What is the total potential energy U, in joules, of the final configuration of three charges? U = || 02 X Otheexpertta.com Grade Summary Deductions Dotential 0% 10001arrow_forwardA rod of pure silicon has a diameter of 2.44 cm and a length of 23.7 cm. The data provided in the table may be useful. Conductivity (σ), resistivity (p), and temperature coefficient of resistivity (a) at 20°C for select materials. material σ (1/(Q2. m)) p (.m) a ('C-¹) conductors silver 6.29 × 107 ☑ 1.59 × 10-8 3.8 × 10-3 copper 5.95 × 107 1.68 × 10-8 3.9 × 10-3 gold 4.10 × 107 2.44 × 10-8 aluminum 3.4 × 10-3 3.77 × 107 2.65 × 10-8 3.9 × 10-3 tungsten 1.79 × 107 ☑ 5.60 × 10-8 4.5 × 10-3 iron 1.03 × 107 9.71 × 10-8 6.5 × 10-3 lead 0.45 × 107 22.0 × 10-8 constantan 0.20 × 107 49.0 × 10-8 0.03 × 10-3 mercury 0.10 × 107 98.0 × 10-8 0.9 × 10-3 nichrome 0.10 × 107 100. × 10-8 0.4 × 10-3 semiconductors carbon (pure) (Values for semiconductors depend strongly on type and amount of impurities.) 2.86 × 10-6 germanium (pure) silicon (pure) 3.50 × 10-5 ☑ 0.60 2300 -0.5 × 10-3 -0.048 -0.075 If a voltage of 1.78 kV is applied across the ends of the rod, what is the resulting current, in millivolts,…arrow_forward
- - - Problem 6: (8% of Assignment Value) Suppose you have a 9.00 V battery, a 2.8 µF capacitor, and a 7.45 µF capacitor. Part (a) ✓ Find the total charge stored in the system if the capacitors are connected to the battery in series in C. Q = 18.36 * 10-6 = 1.836 × 10-5 ✓ Correct! Part (b) Find the energy stored in the system if the capacitors are connected to the battery in series in J. Us = 0.8262 X Incorrect! Part (c) Find the charge if the capacitors are connected to the battery in parallel in C. Part (d) Find the energy stored if the capacitors are connected to the battery in parallel in J. Up=arrow_forwardProblem 1: (8% of Assignment Value) = Three charges are placed at the corners of a rectangle, as shown. The rectangle, with a horizontal side length of h 8.71 cm and a vertical side length of v = 7.40 cm, is aligned with the coordinate axes. The charges at the upper-right, lower-left and lower-right corners are qUR = -6.88 nC, qLL = −8.02 nC, and qLR = −1.44 nC, respectively. ข QLL "L I QUR Part (a) What is the magnitude, in micronewtons, of the net electric force on the charge at the lower-right corner of the rectangle? Fnet = | | μN JLR Grade Summary Deductions Potential 0% 100%arrow_forwardProblem 11: (8% of Assignment Value) The force on a loop of wire in a magnetic field shown in the figure can be used to measure the field strength. The field is uniform, and the plane of the loop is perpendicular to the field. 20.0 cm Bout Otheexpertta.com Part (a) What is the direction of the net magnetic force on the loop? Grade Summary Out of the page. Right Down Into the page. Left Up Submit 2 Submission(s) Remaining Hint Feedback I give up! Deductions Potential Submissions Attempt(s) Remaining: 2 0% Deduction per Attempt detailed view 0% 100% Hints: Part (b) Feedback: If a current of 3.5 A is used, what is the force generated per unit field strength on the 20.0 cm wide section of the loop? Use units of newtons per tesla.arrow_forward
- Problem 5: (8% of Assignment Value) The electric field strength between two parallel conducting plates separated by 4.00 cm is 6.25×10+ V/m. Part (a) ✓ What is the potential difference, in volts, between the parallel conducting plates? V = 2500. V ✓ Correct! Part (b) The electric potential of the lower-potential plate is defined as zero volts. What is the value of the electric potential, in volts, at a point in the gap between the plates that is 2.5 cm from the zero-volt plate? V = || V Grade Summary Deductions 0% 1000farrow_forwardProblem 10: (8% of Assignment Value) A 420 resistor, an uncharged 1.35 µF capacitor, and a battery with a 6.14 V potential difference are connected in series. Randomized Variables R = 420 Q C = 1.35 μF AV = 6.14 V Part (a) What is the initial current in mA, immediately after they are connected? I = || Hints: sin() cos() tan() πο 7 8 9 HOME cotan() asin() acos() E Λ 4 5 6 atan() acotan() sinh() * 1 2 -> cosh() tanh() cotanh() + - 0 END Degrees Radians ✓ BACKSPACE Submit Hint Feedback I give up! 2 Submission(s) Remaining Feedback: Part (b) What is the RC time constant in s? Part (c) What is the current, one time constant after they are connected, in milliamps? Part (d) What is the voltage on the capacitor after one time constant in V? DEL CLEARarrow_forwardProblem 7: (8% of Assignment Value) Consider a parallel plate capacitor having plates of area 1.45 cm² that are separated by 0.022 mm of neoprene rubber. You may assume the rubber has a dielectric constant x 6.7. = Part (a) What is the capacitance in nanofarads? C = 3.91 * 10-4 C = 3.910 × 10-4 nF * Attempts Remain Part (b) What charge, in coulombs, does the capacitor hold when 9.00 V is applied across it? Q = || C Grade Summary Deductions Potentialarrow_forward
- The inclined plate shown in the sketch is supported by two hinges, Band C, attached to a vertical wall, and by a cable AD which exerts a force P-1.72 LN at point A. The cable anchor point D. lies in the y. plane. Hinge B can act as a thrus bearing, but C cannot. The weight of the plate acts at its centre (a) Write the force P as vector components. Determine the weight of the plate and the reactions at hinge Carrow_forwardQC v Rigid rods of negligible mass lying along the y axis connect three particles (Fig. P10.25). The system rotates about the x axis with an angular speed of 2.00 rad/s. Find (a) the moment of inertia about the x axis, Answer (b) the total rotational kinetic energy evaluated from 1/1 I W², Answer (c) the tangential speed of each particle, and Answer (d) the total kinetic energy evaluated from Answer (e) Compare the answers for kinetic energy in parts (a) and (b). Figure P10.25 4.00 kg y= = 3.00 m x 2.00 kg y=-2.00 m 3.00 kg y = -4.00 marrow_forwardi neeg help please and thank youarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
DC Series circuits explained - The basics working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=VV6tZ3Aqfuc;License: Standard YouTube License, CC-BY