Chapter 20.2, Problem 62ES

(A)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{36}-\frac{y^2}{13}=1$ .

(B)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{4}+\frac{y^2}{4}=1$ .

(C)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{25}+\frac{y^2}{16}=1$ .

(D)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{y^2}{25}-\frac{x^2}{39}=1$ .

(E)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{17}+\frac{y^2}{81}=1$ .

(F)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{36}+\frac{y^2}{36}=1$ .

(G)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{16}-\frac{y^2}{65}=1$ .

(H)

To determine

To calculate: The value of $a^2\text{ and }{b}^2$ for the conic section of the equation $\frac{x^2}{144}+\frac{y^2}{140}=1$ .