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Concept explainers
(a)
Interpretation:
Whether or not the given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
(b)
Interpretation:
Whether or not the given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
(c)
Interpretation:
Whether or not the given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
(d)
Interpretation:
Whether or not given sole fact supports the possible identification of the sample as
Concept introduction:
A unit cell of the crystal is the three-dimensional arrangement of the atoms present in the crystal. The unit cell is the smallest and simplest unit of the crystal which on repetition forms an entire crystal. Unit cell can be a cubic unit cell or hexagonal unit cell. The classification of a unit cell depends on the lattice site occupied by the atoms.
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Chapter 21 Solutions
EBK PHYSICAL CHEMISTRY
- (4) Find the Fermi energy of lithium EF, the Fermi temperature TF, and the speed of vF of the fastest free electrons.arrow_forward1) a) A solid substance is considered to be orthorhombic in nature. Since the edges of the unit cell are a = 3.50Å, b = 4.0 Å, c = 5.5 Å, calculate the d and 2θ positions for the 111 plane expected in the diffraction pattern as a result of CuKα radiation (λ = 1.54 Å). b) What is the Miller index of the plane intersecting the crystal axes (2a, 1b, -3c)?arrow_forwardThe largest molecule for which a diffraction pattern has been observed is buckminsterfullerene, C60 (this is an allotrope of carbon in which the atoms are arranged in a pattern similar to that of a soccer ball). The diffraction pattern suggested a molecular wavelength of 2.5 pm. What was the velocity of the fullerenes?arrow_forward
- A crystalline sample has a diffraction peak at 15.6°. What is the corresponding d space in pm? Assume n = 1 and A = 90.1 pm. Report your answer to the ones place.arrow_forwardPlease provide step-by-step anwser What is the probable lattice type of crystalline substances that give the following observed reflections? Body centered? Face centered? Etc.? (a) 100, 110, 111, 200, 210 (b) 001, 110, 200, 111, 201arrow_forwardDefine the term ‘doping’.arrow_forward
- It is thought that a solid substance has an orthorhombic structure. Since the edges of the unit cell are a = 3.50Å, b = 4.0 Å, c = 5.5 Å, calculate the d and 2θ positions for the 111 plane expected in the diffraction pattern as a result of CuKα radiation (λ = 1.54 Å).arrow_forwarda) It is considered that a solid substance has an orthorhombic structure. Since the edges of the unit cell are a = 3.50Å, b = 4.0 Å, c = 5.5 Å, calculate the d and 2θ positions for the 111 plane expected in the diffraction pattern as a result of CuKα radiation (λ = 1.54 Å). b) What is the Miller index of the plane intersecting the crystal axes (2a, 1b, -3c)?arrow_forward(a) Use the Born–Haber cycle, with data from Appendices D and F, to calculate the lattice energy of LiF.(b) Compare the result of part (a) with the Coulomb energy calculated by using an Li-F separation of 2.014 Å in the LiF crystal, which has the rock-saltstructure.arrow_forward
- How does fluorescence work in bulk semiconductors?arrow_forwardWhat are the two reasons that make hydrogen atoms difficult to detect with X-ray diffraction?arrow_forward(e) Platinum has an FCC crystal structure. The atomic radius of platinum is 0.1387 nm. An X-ray diffractometer with a monochromatic radiation of wavelength 0.1542 nm is used is used to analyze a sample of the metal. i. Which of the following planes will produce a peak: (110), (211), or (113)? ii. For the plane producing a peak, calculate its diffraction angle.arrow_forward
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