EBK PHYSICAL CHEMISTRY
2nd Edition
ISBN: 8220100477560
Author: Ball
Publisher: Cengage Learning US
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Chapter 21, Problem 21.53E
Interpretation Introduction
Interpretation:
The lattice energy of
Concept introduction:
The amount of energy released when one formula unit moles of oppositely charged gaseous ions binds together to form a crystal is known as the Lattice energy. The value of lattice energy is negative. It is used as the measure for stability of a crystal.
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Students have asked these similar questions
Calculate the lattice energy of TIF (s) using the
following thermodynamic data (all data is in
kJ/mol). Note that the data given has been
perturbed, so looking up the answer is
probably not a good idea.
TI (S)
TI (g)
F - F
(g)
F (g)
TIF
(s)
AHsublimation = 161
kJ/mol
Ionization energy =
569 kJ/mol
Bond energy = 138
kJ/mol
Electron affinity = -348
kJ/mol
AH°f = -345 kJ/mol
kJ/mol
Given the following thermodynamic data, calculate the lattice energy of LiCl:ΔH°f[LiCl(s)] = -409 kJ/molΔH°sublimation [Li] = 161 kJ/molBond energy [Cl-Cl] = 243 kJ/molIE1 (Li) = 520 kJ/molEA1 (Cl) = -349 kJ/mol
-1682 kJ/mol
-984 kJ/mol
-1560 kJ/mol
-862 kJ/mol
-1213 kJ/mol
Calculate the lattice energy of RbCl using the following data:
AH (k)
Rb(3)
Rb(g)
Chig)
CI(g) + e
Rb(s) + ¾Cl(g}
Rb(g)
Rb"(g) + e¯
86
409
2CI(g)
CF(g)
RÜCI(s)
242
-355
435
Chapter 21 Solutions
EBK PHYSICAL CHEMISTRY
Ch. 21 - Prob. 21.1ECh. 21 - Boron nitride, BN, is a very hard material, harder...Ch. 21 - Prob. 21.3ECh. 21 - Prob. 21.4ECh. 21 - Figure 21.35 shows a unit cell of diamond....Ch. 21 - Prob. 21.6ECh. 21 - How many different unit cells can a crystal have...Ch. 21 - Prob. 21.8ECh. 21 - Prob. 21.9ECh. 21 - Prob. 21.10E
Ch. 21 - Prob. 21.11ECh. 21 - Prob. 21.12ECh. 21 - Prob. 21.13ECh. 21 - Prob. 21.14ECh. 21 - Prob. 21.15ECh. 21 - Prob. 21.16ECh. 21 - Prob. 21.17ECh. 21 - Prob. 21.18ECh. 21 - Prob. 21.19ECh. 21 - Prob. 21.20ECh. 21 - Prob. 21.21ECh. 21 - Prob. 21.22ECh. 21 - Prob. 21.23ECh. 21 - Prob. 21.24ECh. 21 - Prob. 21.25ECh. 21 - Prob. 21.26ECh. 21 - Prob. 21.27ECh. 21 - Prob. 21.28ECh. 21 - For a simple cubic lattice, what is the ratio of...Ch. 21 - Prob. 21.30ECh. 21 - Prob. 21.31ECh. 21 - Consider Figure 21.21. If the lower rightmost...Ch. 21 - Prob. 21.33ECh. 21 - The aluminum-nickel alloy AlNi has a simple cubic...Ch. 21 - Prob. 21.35ECh. 21 - The first two signals from a powdered sample has X...Ch. 21 - Prob. 21.37ECh. 21 - Prob. 21.38ECh. 21 - Prob. 21.39ECh. 21 - Prob. 21.40ECh. 21 - Prob. 21.41ECh. 21 - Prob. 21.42ECh. 21 - Prob. 21.43ECh. 21 - Prob. 21.44ECh. 21 - Prob. 21.45ECh. 21 - What is the coordination number in the cesium...Ch. 21 - Prob. 21.47ECh. 21 - Which solid phase that is, which allotrope of...Ch. 21 - Prob. 21.49ECh. 21 - Prob. 21.50ECh. 21 - Write Born-Haber cycles showing the relationship...Ch. 21 - Prob. 21.52ECh. 21 - Prob. 21.53ECh. 21 - Prob. 21.54ECh. 21 - The lattice energy for potassium iodide, KI, is...Ch. 21 - Prob. 21.56ECh. 21 - Prob. 21.57ECh. 21 - Prob. 21.58ECh. 21 - Prob. 21.59ECh. 21 - Prob. 21.60ECh. 21 - Prob. 21.61ECh. 21 - Prob. 21.62ECh. 21 - Prob. 21.63ECh. 21 - Prob. 21.64E
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Explain the term crystal radii?arrow_forwardCalculate the lattice enthalpy for RbC1. You will need the following information: Species AfH°, kJ/mol Rb(g) RbCl(s) Cl(g) 80.9 - 435.4 121.3 Enthalpy of ionization for Rb(g) is 403.0 kJ/mol; electron attachment enthalpy for Cl(g) is −349.0 kJ/mol. Lattice enthalpy = kJ/molarrow_forwardIn a hydrogen molecule, the two hydrogen atoms are held together by a single bond with a bond energy of 436 kJ/mol of hydrogen. In other words, to break the H-H bonds in one mole of molecular hydrogen requires the expenditure of 436 kJ of energy. Using the balanced chemical equation for the formation of water from oxygen and hydrogen (shown above), and interpreting the stoichiometric coefficients as mole amounts, how much energy must be expended in breaking the H-H bonds? kJarrow_forward
- In a lattice, a positive ion is often surrounded by eight negative ions. We might reason, therefore, that the lattice energy should be related to eight times the potential of interaction between these oppositely charged particles. Why is this reasoning too simple?arrow_forwardCalculate the lattice energy of RbH (s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. AHsublimation 61 kJ/mol Ionization energy = 383 kJ/mol Rb (s) Rb (g) H - H (g) Bond energy = 416 kJ/mol H (g) Electron affinity = -93 kJ/mol RbH (s) AHOf = -72 kJ/mol kJ/molarrow_forwardCalculate the lattice energy of AgCl(s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. Ag(s) AHsublimation 265 kJ/mol Ag(g) Ionization energy 711 kJ/mol Cl-CI(g) Bond energy = 223 kJ/mol CI(g) Electron affinity = -369 kJ/mol AgCl(s) AH°=-147 kJ/mol kJ/mol Do you expect this value to be larger or smaller than the lattice energy of AgBr(s)?arrow_forward
- Calculate the lattice energy,U (in kJ), of the fictitious compound, MCl2, given the following information: ΔHppt for MCl2 = 17.1 kJ/mol, ΔHhyd for M2+ = -450 kJ/mol, ΔHhyd for Cl- = -370 kJ/mol Your answer should have 4 sig figs.arrow_forwardThe lattice energy of magnesium sulfide is the energy change accompanying the process Mg2*(g) + + S2-(g) → MgS(s) Calculate the lattice energy of MgS using the following data: Mg(s) → Mg(g) AH° = 148 kJ/mol Mg(g) → Mg2*(g) + 2e- AH° = 2186 kJ/mol Sg(s) → 8S(g) AH° = 2232 kJ/mol S(g) + 2e-- s2-(g) AH° = 450 kJ/mol 8Mg(s) + Sg(s) → 8MGS(s) AH° = -2744 kJ/mol Mg2*(g) + S2-(g)→ MgS(s) AH°lattice = ?arrow_forwardin organic chemistryarrow_forward
- Based on Kapustinskii equation, calculate the lattice energy of AICI3. Given that: W=1.079 x 105 kJ.pm/mol and ionic radii are: Al3*= 68 pm and Cr= 167 pm. -7528 kJ/mol O- 1378 kJ/mol -5492 kJ/mol -1837 kJ/mol -5510 kJ/molarrow_forwardThe lattice energy of CaO(s) is -3,460 kilojoules per mole; the lattice energy for K2O is -2,240 kilojoules per mole. Account for this difference.arrow_forwardUsing the standard enthalpy of formation data, determine which bond is stronger: the P–Cl bond in PCl3(g) or in PCl5(g)?arrow_forward
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