Chapter 21, Problem 62IAE

Interpretation Introduction

(a)

Interpretation:

To calculate the mass of product obtained.

Concept introduction:

When Ca is heated in air, below reaction is take place.

$\text{2Ca}\left(\text{s}\right){\text{+O}}_{\text{2}}\left(\text{g}\right)\to \text{2CaO}\left(\text{s}\right)$

Molar mass of Ca is $40.078\text{g}$ and molar mass of CaO is $56.0774\text{g/mol}$.

Interpretation Introduction

(b)

Interpretation:

To calculate the mass of ${\text{Ca}}_{\text{2}}{\text{N}}_{\text{2}}$.

Concept introduction:

The mass of product formed from the starting Ca is differ from $0.350\text{g}$ CaO formed, then the product is mixture of ${\text{Ca}}_{\text{3}}{\text{N}}_{\text{2}}$ and $\text{CaO}$. In atmosphere molecular nitrogen is readily available hence, this reaction is possible. The reaction is as follows:

$\text{3Ca}\left(\text{s}\right){\text{+N}}_{\text{2}}\left(\text{g}\right)\to {\text{Ca}}_3{\text{N}}_2\left(\text{s}\right)$

Interpretation Introduction

(c)

Interpretation:

To calculate the mass percent of $\text{CaO}$ in ${\text{CaO-Ca}}_{\text{3}}{\text{N}}_{\text{2}}$ mixed product.

Concept introduction:

To calculate the mass percent of $\text{CaO}$ in ${\text{CaO-Ca}}_{\text{3}}{\text{N}}_{\text{2}}$ mixed product use the formula of percent abundance of an isotope.