Interpretation:
The equation for the reaction between propanoic acid and ethanol is to be written and the ester formed in this reaction is to be named.
Concept introduction:
Carboxylic acid reacts with alcohol to form an ester. This reaction is known as an esterification reaction or condensation reaction. In this reaction, a water molecule is lost. The general structure of an ester is as follows:
Here, R and
The steps to write the IUPAC name of an ester are as follows:
Step 1: Identify the parent chain. The alkyl group from the parent acid represents the parent chain.
Step 2: Number the carbon atoms. Since the parent chain is derived from carboxylic acid, therefore; the name of the parent acid is alkanoic acid. Drop the letters
Step 3: Number the carbon atoms of the alcohol part from the carbon which is directly bonded to the oxygen atom. The alcohol part is named as ‘alkyl’.
Step 4: In the case of ester, an alkyl group of the alcohol is written first followed by the anion of carboxylic acid. The format to name an ester is as follows:
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