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Develop a user-friendly computer program for the multiple-segment
(a) Trapezoidal and
(b) Simpson's 1/3 rule based on Fig. 22.1. Test it by
Use the true value of 0.602298 to compute
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- 6 108 polynomial is used to approximate v8, the answer is: dy 13. of the parametric equations x: 2-3t 3+2t and y =- is dx Use the following information for Questions 14 and 15: 1+t 1+t Using the Newton-Raphson method to determine the critical co-ordinate of the graph y=f(x)=(x)*an (*) (in words x to the power of tan (x)), you will be required to determine f'(x) 14. The expression for f'(x) is: The following tools were required in determining an expression for f'(x): Application of the natural logarithm 15. I. II. The product rule III. Implicit differentiationarrow_forward3. Use the multiple application Simpson's 1/3 rule to estimate the integral of y = sin(x), from x = 0 to 2. Use the number of steps, n = 4. Also, calculate the true error.arrow_forward* :Q4/B/ the value of X-bar is 0.987 1.5 2 2.5 2.5 O 2.5 X 0.398 O 2.5 2.5 0.857 0.55 0.254 0.5 0.487 1.06 0.65arrow_forward
- QUESTION 4 Solve the following differential equation in Matlab using ode45.m. Use time interval of 0.1 second. (Don't use options in ode45 to change teh tolerance.) do (t) dt - cos = sint 0(0)=0. What is e(t=4.1)? ○ 0.871 -0.212 1.44 1.28 2.01 3.19arrow_forwardWhat's the mean of the following points? x = [-3 3 4 2 -1 1 4 5] Type your answer...arrow_forwardUsing trapezoidal rule integration with 2 equal sized sub-intervals, find the area under the curve defined by the polynomial y = 0.10x5 + 0.1x³ + 24 between limits of 4.2 and 11.1. Give your answer to a precision of at least 3 significant figures. Your Answer:arrow_forward
- A root of the function f(x) = x3 – 10x² +5 lies close to x = 0.7. Doing three iterations, compute this root using the Newton- Raphson method with an initial guess of x=1). Newton-Raphson iterative equation is given as: f(x;) Xi+1 = Xị - f'(xi)arrow_forwardTable Error function (erf) values erf (z) erf (2 erf (z) 0.55 0.5033 13 0.9340 0.025 0.0282 O 60 0.6039 14 0.9523 0.05 0.0564 0.05 0 6420 15 0.9001 0.10 0.1125 0.70 0 6778 0.9703 16 0.15 0.1080 0.75 0.7112 1.7 0.9838 0 20 0.2227 080 07421 18 0.0091 025 0 2703 0.85 0.7707 1.9 0.0028 0.30 0.3290 0.90 0.7969 20 0.9953 0.35 03704 0.95 0.8200 22 0.9981 040 0.4284 O 8427 O 8802 1.0 24 0.9903 0.45 0.4755 11 2.6 0.0098 0 50 0.5205 12 0.9103 28 0 9990 A 1010 steel is to be carburized using a gas atmosphere that produces 1.0% Cat the surface of the steel. The case depth is defined as the distance below the surface that contains at least 0.5% Č. If carburizing is done at 1000 C, determine the time required to produce a case depth of 0 234 mm. For the diffusion of Garbon in FCC iron Q - 137.7 kJ/mol and Do = 0.23 x 10 m²/s. The gas constant is R- 8.314 J/(mol - K). Assume that the diffusion coefficient D remains constant and the concentrations of the diffusing atoms at the surface (c.) and at…arrow_forward4. Using the method of Least Squares, determine to 6-decimal place the necessary values of the coefficient C1 and C2 in the equation from the given data points. 1 y = C, + C2x A C 2.07 8.60 14.42 15.8 Where: ABCDEF is your student number. Example, if your student number is 484321. A = 4 B = 8 C = 4 D = 3 5. Using the same data points given in problem 4, solve for the Newton's Interpolating Polynomials.arrow_forward
- 2-the pivot value is the point of the intersection of the row of the leaving variable and the column of the solution. * true falsearrow_forwardmathforadmi..2dff1dd723 PTU Kadoorie sygini 1930 Technical Department of Applied Mathematics Second Semester 2020/2021 Math for Administration Assignment 2 Question 1 For the function: y = 0.01x- 0.001x² Find the zeros, the vertex and the optimum value (max. or min.) Question 2 Suppose a company has fixed costs of $300 and variable 3 costs of x + 1460 dollars per unit, 4 where x is the total number of units produced. Suppose further that the selling price of its product is 1500 X- ♡ lar Fine break-even points. init. II جامعة Palestine ||arrow_forwardA magic square is an arrangement of n numbers into n rows and n columns using distinct numbers from 1 up to n² such that the sum in any row, any column or any of the two diagonals is fixed. Consider the 4 by 4 magic square below: aj a5 2 13 a2 10 11 a7 аз6 а4 12 4 15 a6 1 What is the value of a4 ? 07 O 5 O 16 A Moving to the next question prevents changes to this answer. Question 1 of 3> P Type here to search 9:47 PM 29°C 30-Nov-21 backspe E F C shift alt ctriarrow_forward
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