Bundle: Physical Chemistry, 2nd + Student Solutions Manual
2nd Edition
ISBN: 9781285257594
Author: David W. Ball
Publisher: Cengage Learning
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Question
Chapter 22, Problem 22.16E
Interpretation Introduction
Interpretation:
The reason as to why the same expression is not obtained when the Laplace-Young equation is derived in a different and incorrect way by writing the area of a sphere in terms of volume and then evaluating
Concept introduction:
Laplace-Young equation is a fundamental equation for the behavior of an interface. This equation relates the pressure difference on either side of an interface with the surface tension and the area of the liquid changes with volume. The Laplace-Young equation is shown below.
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Q6. (a)The vander waals equation is used to describe the behaviour
of real gases but still not so useful in many industrial
applications. Explain why?(3)
(b)In kinetic molecular theory of gases it is assumed that
The molecules of the gases occupy negligible volume as compared
to the total volume of the gas' which factor can be actually
described by this postulate?(2)
The energy of the van der Waals bond, which is responsible for a number of the characteristics of water, is about 0.50 eV. (a) At what temperature would the average translational kinetic energy of water molecules be equal to this energy? (b) At that temperature, would water be liquid or gas? Under ordinary everyday conditions, do van der Waals forces play a role in the behavior of water?
c) This relationship is known as Graham's Law of Effusion. Since both gases are at te same temperature, they must
have the same average kinetic energy (½ mv²), where m is mass and v is velocity (like speed). Since both gases have
the same average kinetic
energy, you can state that ½ muvL2 = v ². Multiplying both sides by 2 gives you m v 2 y ². Rearranging the equation to get
H H
LL
H H
2 m
= m
both masses on the same side of the equation will give you mu/mH = V 2/VL2. In 3a and 3b, you probably noticed that the
heavy gas particles took twice as long to diffuse as the light gas particles. This means that the light gas particles are
moving twice as fast, VH/VL = ½. Therefore, V 2/VL2 = ¼. How many times heavier is the heavy gas compared to the
light gas?
d) If the light gas was Ne, what would be a reasonable identity for the heavy gas?
Chapter 22 Solutions
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
Ch. 22 - Using the explanation of unbalanced forces as the...Ch. 22 - Show that the right side of equation 22.1 has...Ch. 22 - The text claims that surface tension varies with...Ch. 22 - Prob. 22.4ECh. 22 - Prob. 22.5ECh. 22 - Prob. 22.6ECh. 22 - Prob. 22.7ECh. 22 - Equation 22.6 defines surface tension in terms of...Ch. 22 - Prob. 22.9ECh. 22 - Prob. 22.10E
Ch. 22 - Prob. 22.11ECh. 22 - Prob. 22.12ECh. 22 - Prob. 22.13ECh. 22 - Prob. 22.14ECh. 22 - Prob. 22.15ECh. 22 - Prob. 22.16ECh. 22 - Prob. 22.17ECh. 22 - Prob. 22.18ECh. 22 - Prob. 22.19ECh. 22 - Determine the pressure difference on a droplet of...Ch. 22 - Prob. 22.21ECh. 22 - Prob. 22.22ECh. 22 - Prob. 22.23ECh. 22 - Prob. 22.24ECh. 22 - Prob. 22.25ECh. 22 - Prob. 22.26ECh. 22 - Prob. 22.27ECh. 22 - The Young-Dupr equation, equation 22.16, is...Ch. 22 - Why are capillary rises and depressions not seen...Ch. 22 - Prob. 22.30ECh. 22 - Prob. 22.31ECh. 22 - Prob. 22.32ECh. 22 - Prob. 22.33ECh. 22 - Prob. 22.34ECh. 22 - Prob. 22.35ECh. 22 - Prob. 22.36ECh. 22 - Prob. 22.37ECh. 22 - Prob. 22.38ECh. 22 - A china cup breaks when the ionic or covalent...Ch. 22 - Satellites in space often suffer from vacuum...Ch. 22 - Prob. 22.41ECh. 22 - Prob. 22.42ECh. 22 - Prob. 22.43ECh. 22 - Are the following processes examples of...Ch. 22 - Prob. 22.45ECh. 22 - Early attempts to coat metals with Teflon, poly...Ch. 22 - Prob. 22.47ECh. 22 - Prob. 22.48ECh. 22 - Prob. 22.49E
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