How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h. Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Question

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Answer 1

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 2

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 3

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 4

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 5

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

Answer 6

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

Answer 7

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Answer 8

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Answer 12

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

Answer 13

Ch. 22.1 - Prob. 22.1QAP Ch. 22.1 - Prob. 22.2QAP Ch. 22.1 - Prob. 22.3QAP Ch. 22.1 - Prob. 22.4QAP Ch. 22.1 - Prob. 22.5QAP Ch. 22.1 - Prob. 22.6QAP Ch. 22.1 - Prob. 22.7QAP Ch. 22.1 - Prob. 22.8QAP Ch. 22.1 - Prob. 22.9QAP Ch. 22.1 - Prob. 22.10QAP

How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h. Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h. Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Answer to Problem 22.83UTC

Explanation of Solution

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Chapter 22 Solutions

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.