   Chapter 2.2, Problem 30E ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

#### Solutions

Chapter
Section ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
1 views

# In Exercises 23 to 32, give the indirect proof for each problem or statement.If a and b are positive numbers, then a 2 + b 2 ≠ a + b .

To determine

To prove:

The given statement.

Explanation

Given:

The given statement is,

If a and b are positive numbers, then a2+b2a+b.

Property:

For any two real numbers a and b,

(a+b)2=a2+b2+2ab

Approach:

Assume that,

a2+b2=a+b

Square both sides of the above equation,

a2+b2=(a+b)2a

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### In Exercises 2340, find the indicated limit. 34. limx1x3+12x3+2

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### What are the two requirements for a random sample?

Essentials of Statistics for The Behavioral Sciences (MindTap Course List)

#### Evaluate the integrals in Problems 7-36. Check your results by differentiation. 33.

Mathematical Applications for the Management, Life, and Social Sciences

#### True or False: f(x) = 10x − x2 is increasing on (4,8).

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 