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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

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BuyFindarrow_forward

Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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Given: M N ¯ N Q ¯ and s as shown
Find: x , y , and z

Chapter 2.4, Problem 16E, Given: MNNQ and  s as shown Find: x, y, and z

To determine

To find:

The value of x, y, and z.

Explanation

Given:

The given statement is,

MN¯NQ¯.

Figure (1)

Properties:

(1) In a triangle, the sum of the measures of the interior angles is 180°.

(2) If two line segments are perpendicular to each other, they intersect at an angle of 90°

(3) Vertically opposite angles are same in measure.

(4) The measure of an exterior angle of a triangle equals the sum of the measures of the two nonadjacent interior angles

Calculation:

The given statement is,

MN¯NQ¯, MNR=65°, RMN=43° and MPR=28°

So,

MNQ=90°RNQ=MNQMNR

Substitute 90° for MNQ and 65° for MNR in the above equation.

RNQ=90°65°RNQ=25°

In ΔRMN,

mRMN+mMNR+mNRM=180°43°+65°+mNRM=180°mNRM=180°43°65°mNRM=72°

NRM is an exterior angle of ΔRMP.

So,

mNRM=mRMP+mMPR

Substitute y for RMP and 28° for MPR, and 72° for NRM in the above equation

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