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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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In Exercises 13 to 15, j k and. Δ A B C .

Given: m 1 = 122.3 ° m 5 = 41.5 °
Find: m 2 , m 3 , and m 4

Chapter 2.4, Problem 15E, In Exercises 13 to 15, jk and. ABC. Given: m1=122.3m5=41.5 Find: m2, m3, and m4

To determine

To find:

The measure of angles m2, m3, and m4.

Explanation

Given:

In ΔABC,

m1=122.3°m5=41.5°jk

Figure (1)

Properties used:

(1) In a triangle, the sum of the measures of all interior angles is 180°.

(2) If two parallel lines are cut by a transversal, then pairs of alternate interior angles are congruent.

(3) Angles on a straight line add up to 180°.

Calculation:

In ΔABC,

m1=122.3°m5=41.5°jk

4 and 5 are two alternate interior angles.

So,

45

Thus,

m4=m5

Substitute 41.5° for m5 in the above equation.

m4=41.5°

1 and 2 are angles on a straight line

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