Explanation Proof: Evaluate the below limit, lim h → 0 cosh − 1 h = 0 Before proving this formula you should know that lim h → 0 sinh h = 1 Consider the limit lim h → 0 cosh − 1 h = lim h → 0 − 2 sin 2 ( h 2 ) h ( sin c e 1 − cos θ = 2 sin 2 ( θ 2 ) ) = lim h

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 2.2, Problem 57PS

To determine

To prove: that limh→0cosh−1h=0 .

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Chapter 2.2, Problem 56PS

Chapter 2.2, Problem 58PS

Chapter 2 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

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To prove: that lim h → 0 cosh − 1 h = 0 .

Solution Summary: The author explains how to prove the formula undersethto 0mathrmlimm

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To prove: that limh→0cosh−1h=0 .

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Chapter 2 Solutions