Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Textbook Question
Chapter 23, Problem 10P
A vertical electric field of magnitude 2.00 × 104 N/C exists above the Earth’s surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 10.0º. Determine the electric flux through the bottom of the car.
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A circular surface with a radius of 0.062 m is exposed to a uniform electric field of magnitude 1.58 × 104 N/C. The electric flux through the surface is 68 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?
A vertical electric field of magnitude 2.00 × 104 N/C exists above the Earth’s surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 10.0º. Determine the electric flux through the bottom of the car.
The surface shown is a square and has a side length of 15.0 cm. The electric field acting on this area has a magnitude of 110. N/C at an angle of 31.9°. Calculate the electric flux through the shown surface.
2.10×104 N m2/C -2.01×104 N m2/C 2.10 N m2/C -1.31 N m2/C
Chapter 23 Solutions
Physics for Scientists and Engineers
Ch. 23.2 - Suppose a point charge is located at the center of...Ch. 23.3 - If the net flux through a gaussian surface is...Ch. 23 - A negatively charged rod of finite length carries...Ch. 23 - A positively charged disk has a uniform charge per...Ch. 23 - A uniformly charged ring of radius 10.0 cm has a...Ch. 23 - The electric field along the axis of a uniformly...Ch. 23 - Example 23.3 derives the exact expression for the...Ch. 23 - A uniformly charged rod of length L and total...Ch. 23 - A continuous line of charge lies along the x axis,...Ch. 23 - A thin rod of length and uniform charge per unit...
Ch. 23 - (a) Consider a uniformly charged, thin-walled,...Ch. 23 - A vertical electric field of magnitude 2.00 104...Ch. 23 - A flat surface of area 3.20 m2 is rotated in a...Ch. 23 - A nonuniform electric field is given by the...Ch. 23 - An uncharged, nonconducting, hollow sphere of...Ch. 23 - Find the net electric flux through the spherical...Ch. 23 - Four closed surfaces, S1 through S4 together with...Ch. 23 - A charge of 170 C is at the center of a cube of...Ch. 23 - (a) Find the net electric flux through the cube...Ch. 23 - A particle with charge of 12.0 C is placed at the...Ch. 23 - A particle with charge Q = 5.00 C is located at...Ch. 23 - A particle with charge Q is located at the center...Ch. 23 - (a) A panicle with charge q is located a distance...Ch. 23 - Find the net electric flux through (a) the closed...Ch. 23 - Figure P23.23 represents the top view of a cubic...Ch. 23 - Determine the magnitude of the electric field at...Ch. 23 - In nuclear fission, a nucleus of uranium-238,...Ch. 23 - Suppose you fill two rubber balloons with air,...Ch. 23 - A large, flat, horizontal sheet of charge has a...Ch. 23 - A nonconducting wall carries charge with a uniform...Ch. 23 - A uniformly charged, straight filament 7.00 m in...Ch. 23 - You are working on a laboratory device that...Ch. 23 - Consider a long, cylindrical charge distribution...Ch. 23 - Assume the magnitude of the electric field on each...Ch. 23 - A solid sphere of radius 40.0 cm has a total...Ch. 23 - A cylindrical shell of radius 7.00 cm and length...Ch. 23 - You are working for the summer at a research...Ch. 23 - You are working for the summer at a research...Ch. 23 - Find the electric flux through the plane surface...Ch. 23 - Three solid plastic cylinders all have radius 2.50...Ch. 23 - A line of charge starts at x = +x0 and extends to...Ch. 23 - Show that the maximum magnitude Emax of the...Ch. 23 - A line of positive charge is formed into a...Ch. 23 - A very large conducting plate lying in the xy...Ch. 23 - A sphere of radius R = 1.00 m surrounds a particle...Ch. 23 - A sphere of radius R surrounds a particle with...Ch. 23 - A slab of insulating material has a nonuniform...Ch. 23 - A sphere of radius 2a is made of a nonconducting...Ch. 23 - An infinitely long insulating cylinder of radius R...Ch. 23 - A particle with charge Q is located on the axis of...Ch. 23 - Review. A slab of insulating material (infinite in...Ch. 23 - Identical thin rods of length 2a carry equal...Ch. 23 - A solid insulating sphere of radius R has a...
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- Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric field E has magnitude 3.50 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines paw through the curved surface. Calculate the electric flux through the cylinder's (a) lop and (b) bottom surface, (c) Determine the amount of charge inside the cylinder. Figure P15.49arrow_forwardFigure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric field E has magnitude 3.50 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines paw through the curved surface. Calculate the electric flux through the cylinder's (a) lop and (b) bottom surface, (c) Determine the amount of charge inside the cylinder. Figure P15.49arrow_forwardThe electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the ball's center and has magnitude 4.0102 N/C. How much charge is on the surface of the ball?arrow_forward
- A uniform horizontal electric field of E = (136 Î +71 Ĵ) N/C passes through an inclined plane that is 52 cm wide and 88 cm long. If the inclined plane makes an angle of 45° with the horizontal, determine the electric flux in the plane in N.m^2/C.arrow_forwardAt what distance along the central axis of a uniformly charged plastic disk of radius R = 1.31 m is the magnitude of the electric field equal to 1/3 times the magnitude of the field at the center of the surface of the disk?arrow_forwardA uniform electric field of strength E = 334 N/C passes through a flat surface at an angle of 0.880 radians. The electric flux is 455 (N/C)·m2. What is the area of the surface?arrow_forward
- A vertical electric field of magnitude 2.00 x 104 N/C exists above the Earth’s surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 10.0°. Determine the electric flux through the bottom of the car.arrow_forward9. A 40.0 cm diameter loop is rotated to the position where the greatest flux is obtained in a uniform electric field. At this location, the flux is measured as 5 .20x10 ^ 5 N.m ^ 2 / C. Find the magnitude of the electric field. 8.14x105N / C2.14x106 NC5.44x106 N / C6.14x106N / C4.14x106N / Carrow_forward
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