CHEMISTRY-ALEK 360 ACCES 1 SEMESTER ONL
CHEMISTRY-ALEK 360 ACCES 1 SEMESTER ONL
12th Edition
ISBN: 9781259292422
Author: Chang
Publisher: MCG
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Chapter 23, Problem 23.35QP
  1. a)
Interpretation Introduction

Interpretation: The number of unpaired electrons in the given complex ions to be predicted.

Concept Introduction:

Crystal field splitting: The splitting of d-orbitals in the presence of ligands is known as crystal field splitting.

Spectrochemical series: The list of ligands arranged in an ascending order of (Δ)(the splitting of d-orbitals in presence of various ligands).

I-<Br-<SCN-<Cl-<S2-<F-<OH-<O2-<H2O<NCS-<edta4-<NH3<  en<NO2-<CN-<COweak-fieldincreasing(Δ)strong-fieldligandsligands

Crystal field splitting: The energy gap between the splitting of d-orbitals of the metal ion in presence of ligands is known as the crystal field splitting (Δ). The magnitude of (Δ) is depends on the nature of metal ions and the ligands.

To Identify: The number of unpaired electrons in the given complex ions to be predicted.

  1. a)
Expert Solution
Check Mark

Answer to Problem 23.35QP

The complex ion [Cr(CN)6]4- has 2 unpaired electrons.

Explanation of Solution

Interpret the complex ion [Cr(CN)6]4-.

CHEMISTRY-ALEK 360 ACCES 1 SEMESTER ONL, Chapter 23, Problem 23.35QP , additional homework tip  1

In complex ion [Cr(CN)6]4- , the oxidation state of chromium ion is +2. The electronic configuration of Cr2+ ion is 4s03d4. The crystal field splitting is large because the cyanide ion is a strong field ligand which gives rise to low-spin complex with respect to Pauling’s exclusion principle. In octahedral splitting; the two (2) number of unpaired electrons present.

  1. b)
Interpretation Introduction

Interpretation: The number of unpaired electrons in the given complex ions to be predicted.

Concept Introduction:

Crystal field splitting: The splitting of d-orbitals in the presence of ligands is known as crystal field splitting.

Spectrochemical series: The list of ligands arranged in an ascending order of (Δ)(the splitting of d-orbitals in presence of various ligands).

I-<Br-<SCN-<Cl-<S2-<F-<OH-<O2-<H2O<NCS-<edta4-<NH3<  en<NO2-<CN-<COweak-fieldincreasing(Δ)strong-fieldligandsligands

Crystal field splitting: The energy gap between the splitting of d-orbitals of the metal ion in presence of ligands is known as the crystal field splitting (Δ). The magnitude of (Δ) is depends on the nature of metal ions and the ligands.

To Identify: The number of unpaired electrons in the given complex ions to be predicted.

  1. b)
Expert Solution
Check Mark

Answer to Problem 23.35QP

The complex ion [Cr(H2O)6]2+ has 4 unpaired electrons.

Explanation of Solution

Interpret the complex ion [Cr(H2O)6]2+.

CHEMISTRY-ALEK 360 ACCES 1 SEMESTER ONL, Chapter 23, Problem 23.35QP , additional homework tip  2

In complex ion [Cr(H2O)6]2+ , the oxidation state of chromium ion is +2. The electronic configuration of Cr2+ ion is 4s03d4. The crystal field splitting is less because the aqua ligand is a weak field ligand which gives rise to high-spin complex with respect to Hund’s rule. In octahedral splitting; the four (4) number of unpaired electrons present.

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Chapter 23 Solutions

CHEMISTRY-ALEK 360 ACCES 1 SEMESTER ONL

Ch. 23 - Why is zinc not considered a transition metal?Ch. 23 - Explain why atomic radii decrease very gradually...Ch. 23 - Without referring to the text, write the...Ch. 23 - Write the electron configurations of the following...Ch. 23 - Why do transition metals have more oxidation...Ch. 23 - Prob. 23.7QPCh. 23 - Prob. 23.8QPCh. 23 - Define the following terms: coordination compound,...Ch. 23 - Describe the interaction between a donor atom and...Ch. 23 - Prob. 23.11QPCh. 23 - Prob. 23.12QPCh. 23 - Prob. 23.13QPCh. 23 - Prob. 23.14QPCh. 23 - Prob. 23.15QPCh. 23 - What are the systematic names for the following...Ch. 23 - Prob. 23.17QPCh. 23 - Prob. 23.18QPCh. 23 - Define the following terms: stereoisomers,...Ch. 23 - Prob. 23.20QPCh. 23 - Prob. 23.21QPCh. 23 - Prob. 23.22QPCh. 23 - Prob. 23.23QPCh. 23 - Prob. 23.24QPCh. 23 - Draw structures of all the geometric and optical...Ch. 23 - Prob. 23.26QPCh. 23 - Briefly describe crystal field theory.Ch. 23 - Prob. 23.28QPCh. 23 - What is the origin of color in a coordination...Ch. 23 - Prob. 23.30QPCh. 23 - Prob. 23.31QPCh. 23 - Prob. 23.32QPCh. 23 - Prob. 23.33QPCh. 23 - Prob. 23.34QPCh. 23 - Prob. 23.35QPCh. 23 - The absorption maximum for the complex ion...Ch. 23 - Prob. 23.37QPCh. 23 - A solution made by dissolving 0.875 g of...Ch. 23 - Prob. 23.39QPCh. 23 - Prob. 23.40QPCh. 23 - Prob. 23.41QPCh. 23 - The [Fe(CN)6]3 complex is more labile than the...Ch. 23 - Aqueous copper(II) sulfate solution is blue in...Ch. 23 - When aqueous potassium cyanide is added to a...Ch. 23 - A concentrated aqueous copper(II) chloride...Ch. 23 - Prob. 23.46QPCh. 23 - As we read across the first-row transition metals...Ch. 23 - Prob. 23.48QPCh. 23 - Prob. 23.49QPCh. 23 - Prob. 23.50QPCh. 23 - Prob. 23.51QPCh. 23 - Chemical analysis shows that hemoglobin contains...Ch. 23 - Explain the following facts: (a) Copper and iron...Ch. 23 - A student in 1895 prepared three coordination...Ch. 23 - Prob. 23.55QPCh. 23 - From the standard reduction potentials listed in...Ch. 23 - Using the standard reduction potentials listed in...Ch. 23 - The Co2+-porphyrin complex is more stable than the...Ch. 23 - Prob. 23.59QPCh. 23 - Prob. 23.60QPCh. 23 - Hydrated Mn2+ ions are practically colorless (see...Ch. 23 - Which of the following hydrated cations are...Ch. 23 - Prob. 23.63QPCh. 23 - Prob. 23.64QPCh. 23 - Prob. 23.65QPCh. 23 - Prob. 23.66QPCh. 23 - The compound 1,1,1-trifluoroacetylacetone (tfa) is...Ch. 23 - Prob. 23.68QPCh. 23 - Prob. 23.69QPCh. 23 - Prob. 23.70QPCh. 23 - Prob. 23.71QPCh. 23 - Commercial silver-plating operations frequently...Ch. 23 - Draw qualitative diagrams for the crystal field...Ch. 23 - (a) The free Cu(I) ion is unstable in solution and...Ch. 23 - Prob. 23.75QPCh. 23 - Prob. 23.76QP
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