ORG.CHEM W/TEXT+SOLU.MANUAL
ORG.CHEM W/TEXT+SOLU.MANUAL
15th Edition
ISBN: 9780393252125
Author: KARTY
Publisher: W.W.NORTON+CO.
Question
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Chapter 23, Problem 23.53P
Interpretation Introduction

(a)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule is to be indicated.

Concept introduction:

Electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decrease electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) electrophilic aromatic substitution in the given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  1

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  2

In the given molecule, benzene has two methoxy substituents. These are activating groups, thus ortho-para directors. Each methoxy group activates their two ortho and one para positions. The activated sites are same for both groups, thus overall there are three activated sites. But the position between two methoxy groups is sterically hindered. Thus, the molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  3

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

Interpretation Introduction

(b)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.

Concept introduction:

Electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activate whereas the electron withdrawing groups deactivate the aromatic ring. The electron donating groups increase the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) of electrophilic aromatic substitution in the given molecule are:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  4

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  5

In the given molecule, benzene has one hydroxyl and one chloride substituent. Both these are activating groups, thus ortho-para directors. Each of the susbtituents activates their two ortho and one para positions. The activated sites are same for both groups thus overall there are three activated sites. But the position between these two substituents is sterically hindered. Thus, molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  6

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

Interpretation Introduction

(c)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.

Concept introduction:

The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increase the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decrease electron density at ortho/para and have comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) of electrophilic aromatic substitution in the given molecule are:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  7

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  8

In the given molecule, benzene has one acetyl and one bromide substituent. Acetyl is carbonyl group which is deactivating thus it is meta director. The bromine atom is activating group thus it is ortho/para director. The acetyl group activates its two meta positions and bromine activates its one ortho and one para positions. The meta positions of acetyl group are same as the ortho/para position of bromine atom. Thus the molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  9

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

Interpretation Introduction

(d)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.

Concept introduction:

The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) of electrophilic aromatic substitution in the given molecule are:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  10

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  11

In the given molecule, benzene has one acetyl and one bromide substituent. Acetyl is carbonyl group which is deactivating thus it is meta director. The bromine atom is activating group thus it is ortho/para director.

The acetyl group activates its one meta positions and bromine activates two ortho and one para positions. The activating sites of both groups are different, thus overall there are three activated sites. But the position between these two substituents is sterically hindered. Thus, molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  12

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

Interpretation Introduction

(e)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.

Concept introduction:

The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) of electrophilic aromatic substitution in the given molecule are:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  13

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  14

In the given molecule, benzene has one nitro and one methyl substituent. Nitro group is deactivating thus it is meta director. The methyl group is activating group thus it is ortho/para director. The nitro group activates its two meta positions and methyl group activates its one ortho and one para positions. The meta positions of nitro group are same as the ortho/para positions of methyl groups. Thus, the molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  15

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

Interpretation Introduction

(f)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.

Concept introduction:

The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) of electrophilic aromatic substitution in the given molecule are:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  16

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  17

In the given molecule, benzene has one methyl and one tert-butyl substituent. They both are activating groups, thus they are ortho/para positions. Each of the susbtituents activates their two ortho positions. The activated sites are not same for both groups so overall there are four activated sites. But the ortho positions of tert-butyl group are sterically hindered. Thus, molecules havee only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  18

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

Interpretation Introduction

(g)

Interpretation:

The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.

Concept introduction:

The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.

Expert Solution
Check Mark

Answer to Problem 23.53P

The most likely site(s) of electrophilic aromatic substitution in the given molecule are:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  19

Explanation of Solution

The given molecule is:

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  20

In the given molecule, benzene has one methyl and one amino substituent. They both are activating groups, thus they are ortho/para positions. Each of the susbtituents activates their two ortho and one para positions. The some activated sites are not same for both groups so, overall there are three activated sites. But the position between two groups is sterically hindered. Thus, molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk (*).

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.53P , additional homework tip  21

Conclusion

The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.

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Chapter 23 Solutions

ORG.CHEM W/TEXT+SOLU.MANUAL

Ch. 23 - Prob. 23.11PCh. 23 - Prob. 23.12PCh. 23 - Prob. 23.13PCh. 23 - Prob. 23.14PCh. 23 - Prob. 23.15PCh. 23 - Prob. 23.16PCh. 23 - Prob. 23.17PCh. 23 - Prob. 23.18PCh. 23 - Prob. 23.19PCh. 23 - Prob. 23.20PCh. 23 - Prob. 23.21PCh. 23 - Prob. 23.22PCh. 23 - Prob. 23.23PCh. 23 - Prob. 23.24PCh. 23 - Prob. 23.25PCh. 23 - Prob. 23.26PCh. 23 - Prob. 23.27PCh. 23 - Prob. 23.28PCh. 23 - Prob. 23.29PCh. 23 - Prob. 23.30PCh. 23 - Prob. 23.31PCh. 23 - Prob. 23.32PCh. 23 - Prob. 23.33PCh. 23 - Prob. 23.34PCh. 23 - Prob. 23.35PCh. 23 - Prob. 23.36PCh. 23 - Prob. 23.37PCh. 23 - Prob. 23.38PCh. 23 - Prob. 23.39PCh. 23 - Prob. 23.40PCh. 23 - Prob. 23.41PCh. 23 - Prob. 23.42PCh. 23 - Prob. 23.43PCh. 23 - Prob. 23.44PCh. 23 - Prob. 23.45PCh. 23 - Prob. 23.46PCh. 23 - Prob. 23.47PCh. 23 - Prob. 23.48PCh. 23 - Prob. 23.49PCh. 23 - Prob. 23.50PCh. 23 - Prob. 23.51PCh. 23 - Prob. 23.52PCh. 23 - Prob. 23.53PCh. 23 - Prob. 23.54PCh. 23 - Prob. 23.55PCh. 23 - Prob. 23.56PCh. 23 - Prob. 23.57PCh. 23 - Prob. 23.58PCh. 23 - Prob. 23.59PCh. 23 - Prob. 23.60PCh. 23 - Prob. 23.61PCh. 23 - Prob. 23.62PCh. 23 - Prob. 23.63PCh. 23 - Prob. 23.64PCh. 23 - Prob. 23.65PCh. 23 - Prob. 23.66PCh. 23 - Prob. 23.67PCh. 23 - Prob. 23.68PCh. 23 - Prob. 23.69PCh. 23 - Prob. 23.70PCh. 23 - Prob. 23.71PCh. 23 - Prob. 23.72PCh. 23 - Prob. 23.73PCh. 23 - Prob. 23.74PCh. 23 - Prob. 23.75PCh. 23 - Prob. 23.76PCh. 23 - Prob. 23.77PCh. 23 - Prob. 23.78PCh. 23 - Prob. 23.79PCh. 23 - Prob. 23.80PCh. 23 - Prob. 23.81PCh. 23 - Prob. 23.82PCh. 23 - Prob. 23.83PCh. 23 - Prob. 23.84PCh. 23 - Prob. 23.85PCh. 23 - Prob. 23.86PCh. 23 - Prob. 23.87PCh. 23 - Prob. 23.88PCh. 23 - Prob. 23.89PCh. 23 - Prob. 23.90PCh. 23 - Prob. 23.91PCh. 23 - Prob. 23.92PCh. 23 - Prob. 23.93PCh. 23 - Prob. 23.94PCh. 23 - Prob. 23.95PCh. 23 - Prob. 23.96PCh. 23 - Prob. 23.97PCh. 23 - Prob. 23.1YTCh. 23 - Prob. 23.2YTCh. 23 - Prob. 23.3YTCh. 23 - Prob. 23.4YTCh. 23 - Prob. 23.5YTCh. 23 - Prob. 23.6YTCh. 23 - Prob. 23.7YTCh. 23 - Prob. 23.8YTCh. 23 - Prob. 23.9YTCh. 23 - Prob. 23.10YTCh. 23 - Prob. 23.11YTCh. 23 - Prob. 23.12YTCh. 23 - Prob. 23.13YTCh. 23 - Prob. 23.14YT
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